Answer:
E = 12262 V/m
Explanation:
given,
Charge of the particle, q = +4.0 μC
mass of the ball, m = 5 g
Electric field, E = ?
Force due to weight
F = m g
Force due to electric field
F =q E
To balance the weight of particle both the forces must be equal
Electric field exerted on the ball will be equal to
m g = q E


E = 12262 V/m
Hence, the electric field acting in the particle is equal to E = 12262 V/m
Answer:
Center of mass lies 24 m in front of center of mass of second wagon.
Explanation:
Suppose A 1200 kg station wagon is moving along a straight highway at 12.0 m/s. Another car with mass 1800 kg and speed 20.0 m/s.
Given that,
Mass of first wagon = 1200 kg
Mass of second wagon = 180 kg
Distance = 40 m
We need to calculate the position of the center of mass of the system
Using formula of center mass



Hence, Center of mass lies 24 m in front of center of mass of second wagon.
I'm probably going to have to say C. E as it seems the steepest right around there. If I'm wrong on that, it has to be B. B
A direct current
this is a current that only flows in one direction