All categories

3 years ago

HELP ASAP

Chemistry

1 answer:

Ket [755]3 years ago

8 0

Answer:

Explanation:

statinary front is when a cold air mass and a warm air mass but are at a standstill the boundry is called statinary front sorry i could not give you other anwsers

You might be interested in

A species that is formed when a base gains conjugate base. b. conjugate acid. a proton is a c. strong base d. strong acid.

SSSSS [86.1K]

Answer:

The correct option is: conjugate acid

Explanation:

Bases are the chemical substances that are proton acceptors and electron-pair donors. Therefore, when a base accepts a hydrogen proton from an acid it forms a conjugate acid.

Therefore, conjugate acids are formed when a base accepts a hydrogen proton from an acid. Also, if the base is a weak base then its conjugate acid is strong. Whereas, if the base is a strong base then the conjugate acid is weak.

4 0

3 years ago

HELP SOMEONE PLEASE I WILL GIVE BRAINLIST I NEED IT NOW PLZ! LOOK AT THE IMAGE ABOVE TO ANSWER

MAVERICK [17]

Answer:

its endothermic .

because your using a cooling process instead of a heating process if it was a heating process it would be exothermic

4 0

3 years ago

Helpppppppp I honestly have no clue

VashaNatasha [74]

North Pole ,land is the answer

3 0

3 years ago

2.61 kilograms of water in a container have a pressure of 200 kPa and temperature of 200°C . What is the volume of this containe

Arisa [49]

Answer: The volume of the container is $2.8497m^3$

Explanation:

To calculate the volume of water, we use the equation given by ideal gas, which is:

$PV=nRT$

or,

$PV=\frac{m}{M}RT$

where,

P = pressure of container = 200 kPa

V = volume of container = ? L

m = Given mass of water = 2.61 kg = 2610 g (Conversion factor: 1kg = 1000 g)

M = Molar mass of water = 18 g/mol

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of container = $200^oC=[200+273]K=473K$

Putting values in above equation, we get:

$200kPa\times V=\frac{2610g}{18g/mol}\times 8.31\text{L kPa }\times 473K\\\\V=2849.7L$

Converting this into cubic meter, we use the conversion factor:

$1m^3=1000L$

So, $\Rightarrow \frac{1m^3}{1000L}\times 2849.7L$

$\Rightarrow 2.8497m^3$

Hence, the volume of the container is $2.8497m^3$

6 0

3 years ago

Which of the following mixtures would result in a buffered solution when 1.0 L of each of the two solutions are mixed?

drek231 [11]

Answer:

c. 0.2 M HNO₃ and 0.4 M NaF .

Explanation:

A buffer is defined as the mixture of a weak acid with its conjugate base or a weak base with its conjugate acid.

A weak acid or weak base are defined as an acid or base that partially dissociates in aqueous solution. in contrast, a strong acid or base are acids or bases that is dissociated completely in water.

Thus:

a. 0,2M HNO₃ and 0.4 M NaNO₃. This is a mixture of a strong acid with its conjugate base. IS NOT a buffer.

b. 0.2 M HNO₃ and 0.4 M HF . This is a mixture of two strong acids. IS NOT a buffer.

c. 0.2 M HNO₃ and 0.4 M NaF . NaF is the conjugate base of a weak acid as HF is.

The reaction of HNO₃ with NaF is:

HNO₃ + NaF → HF + NaNO₃

That means that in solution you will have a weak acid (HF) with its conjugate base (NaF). Thus, this mixture IS a buffer.

d. 0.2 M HNO₃ and 0.4 M NaOH. This is the mixture of a strong acid with a strong base, thus, this IS NOT a buffer.

I hope it helps!

7 0

3 years ago