Taking into account the animals and the landscape being mentioned, we can confirm that the combination of these forms<u><em> part of an </em></u><u><em>ecosystem</em></u><u><em>.</em></u>
An ecosystem is described as an area consisting of:
- Plants
- Animals
- Bacteria
- Weather
- Landscape
and many other factors, which all work together to form a small pocket of life.
Ecosystems are described as containing both living and non-living elements, meaning biotic and non-biotic parts. A community or population, on the other hand, <u>are used to consider only the </u><u>biotic </u><u>or </u><u>living factors </u><u>of an </u><u>ecosystem</u><u>. </u>Therefore, since the question includes the rock bottom (a<em><u> non-biotic factor</u></em>) as a part of the makeup, the only correct grouping is that of an ecosystem.
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What do you mean do you need hekp?
From the equation; ΔTf = Kf × m
Where, Kf for water = 1.853 K kg/mole; m is the molarity = number of solute/amount of solvent in kg.
Glucose is the solute whose molecular mass is 180 g/mole and water is the solvent.
Moles of solute = 15.5/180 = 0.0861 moles
Amount of solvent in kg = 245/1000 = 0.245 Kg
Therefore; molarity = 0.0861/0.245 = 0.3515 moles/Kg
Therefore; ΔTf = 1.853 × 0.3515 = 0.6513 K
Hence; the depression in freezing point is 0.6513
The freezing point of solution will therefore be;
= 273 - 0.6513 = 272.3487 K
Answer:
The volume will be 89.6875 ml
Explanation:
So to count this we will use a single proportion.
0.0640 mol - 1000 ml
5.74×10−3 mol - x ml
x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml
A fan pulls in air from the surrounding area, which typically has high moisture levels.
When the air passed through the dehumidifier , it touches the cooling coils , which in turn pull moisture from the air by lowering temperature.
