Ground state of Al is 1s²2s²2p⁶3s²3p¹.
Exited state of Al is 1s²2s²2p⁶3s¹3p².
What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have
![PV = nRT](https://tex.z-dn.net/?f=%20PV%20%3D%20nRT%20)
or
![n = \frac{PV}{RT}](https://tex.z-dn.net/?f=%20n%20%3D%20%5Cfrac%7BPV%7D%7BRT%7D%20)
where R is <span>0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.
Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R.
</span>
Thus, we have
P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L
Now, applying these converted values into the gas law, we have
![n = \frac{(0.968 atm)(0.250 L)}{(0.08206 L.atm/mol.K)(301.15 K)}](https://tex.z-dn.net/?f=%20n%20%3D%20%5Cfrac%7B%280.968%20atm%29%280.250%20L%29%7D%7B%280.08206%20L.atm%2Fmol.K%29%28301.15%20K%29%7D%20)
![n = 0.00979 moles](https://tex.z-dn.net/?f=%20n%20%3D%200.00979%20moles%20)
Given that the mass of the sample is 0.430 g, we have
![molar mass = \frac{0.430}{0.00979} = 43.9](https://tex.z-dn.net/?f=%20molar%20mass%20%3D%20%5Cfrac%7B0.430%7D%7B0.00979%7D%20%3D%2043.9%20)
Thus, the gas sample has a molar mass of 43.9 g/mol.
Answer:
D
Explanation:
I believe the answer is D because atoms are always seeking to fill up their outer electron shell/valence shell and want to gain a full octet.
Answer:
I think it's A
Explanation:
Carbon dioxide is added to the atmosphere whenever people burn fossil fuels. ... As the amount of carbon dioxide in the atmosphere rises, the oceans absorb a lot of it. In the ocean, carbon dioxide reacts with seawater to form carbonic acid. This causes the acidity of seawater to increase.
Answer:
Earth's atmosphere is divided into five main layers: the exosphere, the thermosphere, the mesosphere, the stratosphere and the troposphere.
Explanation: