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Aleks04 [339]
4 years ago
9

How could you separate a mixture of rocks and sand?

Chemistry
1 answer:
ryzh [129]4 years ago
3 0
To separate a mixture of rocks and sand I think water will be the best option to break it down
You might be interested in
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

8 0
3 years ago
Read 2 more answers
If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?
Igoryamba
The correct answer is 12.2% BaO.

The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
\frac{25.8}{212}*(100) =12.2%
3 0
3 years ago
What is the mass of alliminum?
Gennadij [26K]

Answer:

26.981539 u

Atomic number: 13

Symbol: Al

Electron configuration: [Ne] 3s²3p¹

5 0
3 years ago
Read 2 more answers
The table describes how some substances were formed.
lisabon 2012 [21]

Explanation:

Which is a pure substance?

1. soda

2. gasoline

3. salt water

4. carbon dioxide

carbon dioxide

Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of -7.2°C. Bromine can be classified as a

1. compound.

2. impure substance.

3. mixture.

4. pure substance.

pure substance.

6 0
3 years ago
Read 2 more answers
The reaction of NO2 with ozone produces NO3 in a second-order reaction overall.
Brilliant_brown [7]

Answer :  The rate of reaction is,

Rate=4.77\times 10^{-19}M/s

The appearance of NO_3 is, 4.77\times 10^{-19}M/s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

NO_2(g)+O_3(g)\rightarrow NO_3(g)+O_2(g)

The rate law expression will be:

Rate=k[NO_2][O_3]

Given:

Rate constant = k=1.69\times 10^{-4}M^{-1}s^{-1}

[NO_2] = 1.77\times 10^{-8}M

[O_3] = 1.59\times 10^{-7}M

Rate=k[NO_2][O_3]

Rate=(1.69\times 10^{-4})\times (1.77\times 10^{-8})\times (1.59\times 10^{-7})

Rate=4.77\times 10^{-19}M/s

The expression for rate of appearance of NO_3 :

\text{Rate of reaction}=\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}

As, \text{Rate of reaction}=4.77\times 10^{-19}M/s

So, \text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}=4.77\times 10^{-19}M/s

Thus, the appearance of NO_3 is, 4.77\times 10^{-19}M/s

7 0
3 years ago
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