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Annette [7]
2 years ago
5

2 moles of a monatomic ideal gas is placed under a piston in a cylindrical container. The piston can move freely up and down wit

hout friction and its diameter is 20 cm. A 50 kg weight i placed on the top of the piston. The initial temperature of the gas is 0°C. A. Calculate the absolute pressure in the container. B. Calculate the volume of the gas. D. Calculate the amount of work done by the gas during its expansion.​
Physics
1 answer:
Leto [7]2 years ago
3 0

The absolute pressure in the container when the monatomic ideal gas is placed under a piston is 1.17 × 10⁵ pa

<h3>How to calculate pressure?</h3>

The absolute pressure in the container will be:

= Po + mg/A

= 1.013 × 10⁵ + (50 × 9.8)/(π × 0.1²)

= 1.17 × 10⁵ pa

The volume of the gas will be:

= nRT/P

= 2 × 8 × 3.14 × (0 + 273)/(1.17 × 10⁵)

= 0.0388m³

The amount of work done by the gas during its expansion will be:

= 1.17 × 10⁵ × (0.053 - 0.0388)

= 1661J

Learn more about pressure on:

brainly.com/question/25736513

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Calculate the lowest energy (in ev) for an electron in an infinite well having a width of 0.050 mm.
MA_775_DIABLO [31]

The lowest energy of electron in an infinite well is 1.2*10^-33J.

To find the answer, we have to know more about the infinite well.

<h3>What is the lowest energy of electron in an infinite well?</h3>
  • It is given that, the infinite well having a width of 0.050 mm.
  • We have the expression for energy of electron in an infinite well as,

                  E_n=\frac{n^2h^2}{8mL^2}

  • where;

                m=9.1*10^{-31}kg\\L=0.050*10^{-3}m\\h=6.63*10^{-34}Js\\n=1

  • Thus, the lowest energy of electron in an infinite well is,

                E_1=\frac{(6.63*10^{-34})^2}{8*9.1*10^{-31}*(0.050*10^{-3})}=1.2*10^{-33}J

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.

Learn more about the infinite well here:

brainly.com/question/20317353

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