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gregori [183]
3 years ago
9

For mechanical waves, such as sound waves or ocean waves, increasing the intensity of the wave increases both the amplitude (hei

ght) of the wave and the energy it carries. In that situation, a low-frequency but high-intensity wave should have the same effect as a high-frequency but low-intensity wave. How does light behave differently from this model?
Physics
2 answers:
Norma-Jean [14]3 years ago
5 0

Answer:

the effect is given by the energy that depends on the frequency, but not on the intensity

Explanation:

There are similarities and differences between mechanical waves and electromagnetic waves. The main difference is that mechanical waves depend on a material medium for their propagation, whereas electromagnetic waves are maintained by the oscillation of their electrical magnetoscope fields.

In the case of light (electromagnetic wave) the energy is given by the relation

          E = h f

where h is Planck's constant and f is the frequency.

Then the intensity is given by the number of waves or quasiparticles (photons) that are in the ray.

Consequently the effect is given by the energy that depends on the frequency, but not on the intensity

Novosadov [1.4K]3 years ago
4 0

Answer:

the effect is given by the energy that depends on the frequency, but not on the intensity

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<u>Answer</u>

3 Ohms

<u>Explanation</u>

when the resistors are in series, the resistance in the circuit increases. For example, if two resistors, R1 and R2 are in series, the combined resistance is R1+R2.

When connected in parallel, the total resistance is the reciprocal of (1/R1 + 1/R2)

In this case the resistors are in parallel.

Total resistance = (1/12 + 1/4)⁻¹

= (1/3)⁻¹

= 3 Ohms

7 0
3 years ago
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A small omnidirectional stereo speaker produces waves in all directions that have an intensity of 8.00 at a distance of 4.00 fro
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Answer:

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total power = power/ Area ( 4πr2)= 8.00 w/m^2( 4π ( 4.00 m)2=1607.68 W

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Sedaia [141]

Answer:

V = 20.5 m/s

Explanation:

Given,

The mass of the cart, m = 6 Kg

The initial speed of the cart, u = 4 m/s

The acceleration of the cart, a = 0.5 m/s²

The time interval of the cart, t = 30 s

The final velocity of the cart is given by the first equation of motion

                              v = u + at

                                  = 4 + (0.5 x 30)

                                = 19 m/s

Hence the final velocity of cart at 30 seconds is, v = 19 m/s

The speed of the cart at the end of  3 seconds

                                    V = 19 + (0.5 x 3)

                                       = 20.5 m/s

Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s

6 0
3 years ago
Question 1 (1 point)
IrinaK [193]
  1.  momentum  
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  3. Fullback  
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  8. it stays the same
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<h3><u><em>these are all correct i got an 100%</em></u><em><u> </u></em></h3>
8 0
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