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Gekata [30.6K]
3 years ago
10

Please answer of of them.​

Physics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

1. 7.5 km/h

2. 1 hour, 52 minutes, 30 seconds

3. 0.8 Joules

4. 13.33 mph

5. 19456 Joules

6. 10.5 kg

Explanation:

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A paper-filled capacitor is charged to a potential difference of V 0 = 2.5 V V0=2.5 V . The dielectric constant of paper is κ =
forsale [732]

Answer:

V_1=9.25 V

Explanation:

We are given that

V_0=2.5 V

k=3.7

We have to find the new potential difference of the capacitor.

When the capacitor is disconnected then the charge stored in capacitor is constant.

When we introduce material of dielectric constant k between the plates of capacitor then the capacitance of capacitor increases k times.

C_0=\frac{Q}{V_0}

C'=kC=\frac{kQ}{V_1}

\frac{Q}{V_0}=\frac{kQ}{V_1}

V_0=\frac{V_1}{k}

Using the formula

V_0=\frac{V_1}{k}

V_1=V_0k=2.5\times 3.7=9.25 V

Hence, the new potential difference V_1=9.25 V

5 0
3 years ago
Fees associated with buying and finalizing your loan are known as
-BARSIC- [3]

closing cost is the term to describe Fees associated with buying and finalizing your loan.

5 0
4 years ago
A child bounces a 48 g superball on the sidewalk. The velocity change of the superball is from 28 m/s downward to 17 m/s upward.
Aliun [14]

Answer:

F = 1.2×10⁻³ N

Explanation:

From the question,

Applying newton's second law of motion,

F = m(v-u)/t................... Equation 1

Given: F = magnitude of the average force exerted on the ball, m = mass of the ball, v = final velocity, u = initial velocity, t = time of  contact.

Note: let downward be negative and upward be positive.

Given: m = 48 g = 48/1000 = 0.048 kg, v = 17 m/s, u = -28 m/s (downward),

t = 1800 s

Substitute into equation 1

F = 0.048(17-[28])/1800

F = 1.2×10⁻³ N

7 0
3 years ago
A 6 kg bowling ball moves with a speed of 3 m/s. How fast does a 7 kg bowling ball need to move so that it has the same kinetic
maw [93]

Answer: 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy.

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{1}{2}mv^2

m = mass of object

v= velocity of the object

K.E=\frac{1}{2}\times 6kg\times (3m/s)^2=27Joules

b) for a 7 kg bowl to have kinetic energy of 27 Joules:

27J=\frac{1}{2}\times 7kg\times v^2

v^2=7.7

v=2.8m/s

Thus 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy

4 0
3 years ago
How long would it take an object to reach the ground from the top of a building that is 470 feet tall? Round to the nearest tent
Zinaida [17]

Answer:

It would take the object 5.4 s to reach the ground.

Explanation:

Hi there!

The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:

h = h0 + v0 · t + 1/2 · g · t²

Where:

h = height of the object at time t.

h0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).

t = time

Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:

h = h0 + 1/2 · g · t²

We have to find the time at which h = 0:

0 = 470 ft - 1/2 · 32.2 ft/s² · t²

Solving for t:

-470 ft = -16.1 ft/s² · t²

-470 ft / -16.1 ft/s² = t²

t = 5.4 s

3 0
4 years ago
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