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mr_godi [17]
3 years ago
8

Lead crystallizes in a face-centered cubic structure with a density of 11.34 g/cm3. Polonium crystallizes in a simple cubic stru

cture with a density of 9.3 g/cm3. Explain why lead has a greater density than polonium even though polonium atoms are heavier, and smaller than lead atoms.
Chemistry
2 answers:
malfutka [58]3 years ago
8 0

Answer:

Explanation:

In a face-centered cubic structure, each unit cell has 4 atoms. Each of the 8 corner atoms contribute 1/8 part to the unit cell and each of the 6 atoms at face-centres contribute 1/2 part to the unit cell. So, each unit cell has net 4 atoms.

In a simple cubic structure, there are 8 atoms, one at each corner. So, each one of them contribute 1/8 part to the unit cell. So, the unit cell has only 1 atom effectively.

Hence, each cell units of lead has 4 times as atoms as in the unit cells of polonium.

Due to this, density of lead is higher despite the fact that it's atomic mass is smaller and the size is bigger than that of a polonium atom.

Cloud [144]3 years ago
8 0

Answer:

The face-centered cubic structure is characterized in that there are four atoms in each unit cell. Each atom located in a corner corresponds one eighth of the unit cell and the atoms located in the center correspond a medium of the unit cell. This results in that in each unit cell it has four atoms.

On the other hand, in the simple cubic structure there are eight atoms, located at each corner. Each of these atoms contributes one eighth of the unit cell. Therefore, in each unit cell there is only one atom.

In each cell of the element lead contains four times more atoms than in the cell of polonium. This means that lead is much denser and larger than the element polonium.

Explanation:

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3 years ago
The reaction for the combustion of methane is shown below. If 28.70g of methane
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3 years ago
Based on the following unbalanced reaction. how many moles of U can be 2 produced when you produce 3 moles of Z?
oee [108]

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9

Explanation:

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3 years ago
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4 0
3 years ago
A small hole in the wing of a space shuttle requires a 15.9 cm2 patch.
Rzqust [24]

The patch area in square kilometers is 1.59*10⁻⁹ km₂

Why?

This is an unit conversion problem. We have to convert from cm² to km². We can do that by knowing that there are 100 cm in 1 m, and 1000 m in 1 km, so 100000 cm=1km. Knowing that we can apply the following conversion factor:

15.9 cm^{2} * (\frac{1 km}{100000 cm} )^{2}=0.00000000159 km^{2}

Now to convert this value to scientific notation, we have to move the decimal point to the right until we get a whole number, and the exponent of the number 10 is going to be the number of spaces we moved to the right (negative), so the final answer is:

0.00000000159 km^{2}=1.59*10^{-9} km^{2}

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