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Anit [1.1K]
2 years ago
12

soaps do not work well in hard waters. But they can still be effected it large quantities of soap are added to water. Explain wh

y.​
Chemistry
2 answers:
Nookie1986 [14]2 years ago
6 0

They can still be effected it large quantities of soap are added to water

because more soap eliminates the effect the minerals in hard water has on

its cleaning capacity.

Hard water contains minerals such as

  • Calcium
  • Magnesium
  • Iron etc.

They reduce the cleaning capacity of the soap. This is why soft water is

preferably used as it doesn't contain these minerals.

When more soap is added, the effect of the minerals reduces thereby

bringing about very little or no effect on the cleaning capacity of the soap.

Read more about Soap here brainly.com/question/1473301

Yakvenalex [24]2 years ago
5 0

Explanation:

Ordinary water does not remove dirt from clothes or skin because the dirt present is oily or greasy in nature. Soaps are one of the most commonly used cleansing agents and are capable of reacting with water to remove dirt. They are either animal origin or plant in origin.

Chemically, they are water soluble sodium or potassium salts of higher fatty acids such as stearic acid, palmitic acid or oleic acid. Fatty acids are found in fats and oils. When fat or oil is treated with alkali such as caustic soda or caustic potash soap and glycerin are produced.

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castortr0y [4]
Oxidation number is charge of element in compound. Can be neutral, positive or negative.
Oxygen in dichromate has oxidation number -2, becauce there are seven oxygens, net oxidation number of oxygen is -14.
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8 0
3 years ago
245 g water sample initially at at 32 oC absorbs 17 kcal of heat. What is the final temperature of water?
steposvetlana [31]

Answer:62.66°C or 235.66K

Explanation:Q=McpT, the energy was given in calories so you first convert to Joules by multiplying the value in calories by 4.184J.

17*4.184=71.128kJ.

71.128kJ=mcpT

71.128kJ=245*4.187*(T-Tm)

Tm is the final temperature of the mixture. The T is the temperature given which should be converted to Kelvin by adding 273...T=32+273=305K.

71128J=245*4.187*(305-Tm)

71128=312873.575-1025.815Tm

1025.815Tm=312873.575-71128

1025.815Tm=241745.58

Tm=241745.58/1025.815

Tm=235.66K

4 0
3 years ago
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Therefore, the answer is B. MELTING OF COPPER
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Answer:

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