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Anit [1.1K]
2 years ago
12

soaps do not work well in hard waters. But they can still be effected it large quantities of soap are added to water. Explain wh

y.​
Chemistry
2 answers:
Nookie1986 [14]2 years ago
6 0

They can still be effected it large quantities of soap are added to water

because more soap eliminates the effect the minerals in hard water has on

its cleaning capacity.

Hard water contains minerals such as

  • Calcium
  • Magnesium
  • Iron etc.

They reduce the cleaning capacity of the soap. This is why soft water is

preferably used as it doesn't contain these minerals.

When more soap is added, the effect of the minerals reduces thereby

bringing about very little or no effect on the cleaning capacity of the soap.

Read more about Soap here brainly.com/question/1473301

Yakvenalex [24]2 years ago
5 0

Explanation:

Ordinary water does not remove dirt from clothes or skin because the dirt present is oily or greasy in nature. Soaps are one of the most commonly used cleansing agents and are capable of reacting with water to remove dirt. They are either animal origin or plant in origin.

Chemically, they are water soluble sodium or potassium salts of higher fatty acids such as stearic acid, palmitic acid or oleic acid. Fatty acids are found in fats and oils. When fat or oil is treated with alkali such as caustic soda or caustic potash soap and glycerin are produced.

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Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)

Half reactions of oxidation and reduction are :

Oxidation : Fe(s)\rightarrow Fe^{3+}+3e^-        ......(1)

Reduction : 2I^-(aq)+2e^-\rightarrow I_2         .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : 2Fe(s)\rightarrow 2Fe^{3+}+6e^-        ......(1)

Reduction : 6I^-(aq)+6e^-\rightarrow 3I_2         .......(2)

The overall balanced chemical reaction will be:

2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

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