<em>Train A = 214 </em>
<em> Train B = 86</em>
<em>Hope I helped!!! ^^</em>
<em>_______________</em>
<em>列車A = 214 </em>
<em> 列車B = 86 </em>
<em>私が助けてくれたらいいのに！^ ^</em>
36p+18+8=-35 solve for p
2 answers:
You might be interested in
Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:
Now the lowest 80% of the amount invested can be represented as follows:
The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:
Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.