The answer would be acceleration.
Answer:
(A) Impulse = 9Ns
(B) F = 1286N
Explanation:
Impulse = change in momentum = m(v-u)
v = 0 (the hand comes to a stop)
u = -10m/s
Mass = 0.9kg
Impulse = 0.9 ×(0- (-10))
= 9Ns
(B) F×t = Impulse
F = Impulse/ t
t = 7ms = 7×10-³
F = 9/ (7×10-³)
F = 1286N.
It’s going 3m/s. If we have 5 seconds to work with then we can find the acceleration by adding speed and how fast it going every second. So like the 7-10-13-16-19 so we go 3m/s faster ever second
Hi there!
Acceleration:
a = Δv / Δt, so:
a = 20/9 ≈ 2.22 m/s²
Displacement:
We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).
Δd = 1/2at²
Plug in the acceleration and time:
Δd = 1/2(2.22)(9)² ≈ 89.91 m
