Find the average acceleration of a northbound subway train that slows down from 12 m/s to 9.6 m/s in 0.8 seconds.
1 answer:
Answer:
Explanation:
Given that,
Initial speed of a train, u = 12 m/s
Final speed of a train, v = 9.6 m/s
Time taken, t = 0.8 s
We need to find the average acceleration of the train. We know that the rate of change of velocity is equal to acceleration. So,
So, the average acceleration of the train is equal to .
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Answer:
a)
b)
c) Generally the most probable speed is 8m/s as it the most posses by particles being the average
Explanation:
From the question we are told that:
Sample size N=15
Generally the equation for Average speed is mathematically given by
Therefore
b)
Generally the equation for RMS speed of the particle is mathematically given by
c
Generally the most probable speed is 8m/s as it the most posses by particles being the average
Answer:
average value of the resulting force
Explanation:
The average module value of this resulting force is equivalent to 2.0. 10⁵ N.
The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -
I = F.Δt
Where,
F = Strength in Newtons
Δt = time interval in seconds
I = Impulse in N.s
The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.
I = ΔQ
The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.
Q = m-V
As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.
I = 0 - mV
F. Δt = - mV
F. 0,1 = - 1000. 20
F = - 20000/0,1
F = 200,000 N
F = 2,0. 10⁵ N
