Question

 Find the average acceleration of a northbound subway train that slows down from 12 m/s to 9.6 m/s in 0.8 seconds.​

Answer 1

Answer:

$a=-3\ m/s^2$

Explanation:

Given that,

Initial speed of a train, u = 12 m/s

Final speed of a train, v = 9.6 m/s

Time taken, t = 0.8 s

We need to find the average acceleration of the train. We know that the rate of change of velocity is equal to acceleration. So,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{9.6-12}{0.8}\\\\a=-3\ m/s^2$

So, the average acceleration of the train is equal to $-3\ m/s^2$.