All categories

3 years ago

Click the location of the point in the coordinate plane with the coordinates (–4, 3).

Mathematics

1 answer:

DerKrebs [107]3 years ago

8 0

Answer:

I've put the red dot where location is.

Step-by-step explanation:

You might be interested in

PLEASE HELPPPP

VladimirAG [237]

Answer:

x=2

Step-by-step explanation:

8x-13y=16

8x-13(0)=16

8x=16

---------

8 8

-----------

x=2

4 0

3 years ago

I need help with this

Phantasy [73]

Answer:
it means that -76<-45

-76 is less than -45

7 0

2 years ago

What is the domain of the relation?

timofeeve [1]

Answer:

-4 ≤ x ≤ 6

Step-by-step explanation:

When we talk of the domain, we are referring to the possible x-values

from the diagram, we can see that we have the x-values at -4 and 6

The dotted line means that -4 and 6 are in the domain

Thus, the two points represent the end and starting point of the domain

Writing this in interval notation, we have the representation as;

-4 ≤ x ≤ 6

3 0

3 years ago

Verify that the function u(x, y, z) = log x^2 + y^2 is a solution of the two dimensional Laplace equation u_xx + u_yy = 0 everyw

Daniel [21]

Answer:

The function $u(x,y,z)=log ( x^{2} +y^{2})$ is indeed a solution of the two dimensional Laplace equation $u_{xx} +u_{yy} =0$ .

The wave equation $u_{tt} =u_{xx}$ is satisfied by the function $u(x,t)=cos(4x)cos(4t)$ but not by the function $u(x,t)=f(x-t)+f(x+1)$ .

Step-by-step explanation:

To verify that the function $u(x,y,z)=log ( x^{2} +y^{2})$ is a solution of the 2D Laplace equation we calculate the second partial derivative with respect to x and then with respect to t.

$u_{xx}=\frac{2}{ln(10)}((x^{2} +y^{2})^{-1} -2x^{2} (x^{2} +y^{2})^{-2})$

$u_{yy}=\frac{2}{ln(10)}((x^{2} +y^{2})^{-1} -2y^{2} (x^{2} +y^{2})^{-2})$

then we introduce it in the equation $u_{xx} +u_{yy} =0$

we get that $\frac{2}{ln(10)} (\frac{2}{(x^{2}+y^{2}) } - \frac{2}{(x^{2}+y^{2} ) } )=0$

To see if the functions 1) $u(x,t)=cos(4x)cos(4t)$ and 2) $u(x,t)=f(x-t)+f(x+1)$ solve the wave equation we have to calculate the second partial derivative with respect to x and the with respect to t for each function. Then we see if they are equal.

1) $u_{xx}=-16 cos (4x) cos (4t)$