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Zigmanuir [339]
3 years ago
13

What are the degree and zeros of the polynomial f(x)=(x-1)(x-2)^2(x-pi)^3

Mathematics
2 answers:
Vinil7 [7]3 years ago
4 0

Answer:

The degree is 6, and the zero is 0

Step-by-step explanation:

Hope this helps! :) ~Zane

P.S. sorry if im wrong with the zero one

ziro4ka [17]3 years ago
4 0

Answer:

Degree 6; Zeros 1, 2, pi

Step-by-step explanation:

Answer choice B on Edge

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Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
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Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
2 years ago
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