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horsena [70]
3 years ago
8

Hey it's 10 points related to maths

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

12 apple in a small box.

Step-by-step explanation:

If there's 100 in a large box, then subtract the 4 loose apples to only have left 96 apples among the 8 small boxes. 96/8 is 12 apples per small box

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the first one: Valido’s Conduct under Review

the second: by removing “unpopular” and “conservative”

the third: by adding a comment from Republican senator

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3 years ago
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Solve the following system of equations.<br> 4x-2y-z=-5<br> x-3y+2z=3<br> 3x+y-2z=-5
Stels [109]
4x - 2y - z = - 5 ______×2x - 3y + 2z = 3 _______×13x + y - 2z = - 5 ______×1
8x - 4y - 2z = - 10x - 3y + 2z = 33x + y - 2z = - 5
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3 0
3 years ago
Please help me I don't know
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5 0
4 years ago
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Find The Value of X<br> A. 10<br> B. 14<br> C. 9<br> D. 16
storchak [24]

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8 0
2 years ago
The length of a violin string varies inversely with the frequency of its vibrations. A violin string 14 inches long vibrates at
lara31 [8.8K]

Answer: 525 cycles per second.

Step-by-step explanation:

The equation for inverse variation between x and y is given by :-

x_1y_1=x_2y_2       (1)

Given : The length of a violin string varies inversely with the frequency of its vibrations.

A violin string 14 inches long vibrates at a frequency of 450 cycles per second.

Let x =  length of a violin

y=  frequency of its vibrations

To find: The frequency of a 12 inch violin string.

Put x_1=14,\ x_2=12\\y_1=450,\ y_2=y in equation (1) , we get

(14)(450)=(12)(y)  

Divide both sides by 12 , we get

y=\dfrac{(14)(450)}{12}=525

Hence, the frequency of a 12 inch violin string = 525 cycles per second.

3 0
3 years ago
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