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guapka [62]
2 years ago
14

A bag contains 10 marbles: 2 are green, 4 are red, and 4 are blue. Carlos chooses a marble at random, and without putting it bac

k, chooses another one at random. What is the probability that the first marble was blue and the second is green? Write answer as a fraction in simplest form.
Mathematics
2 answers:
Sveta_85 [38]2 years ago
5 0

Step-by-step explanation:

The fraction is 4/10 * 2/9 = 4/45.

valina [46]2 years ago
5 0

Answer:

The probability is 4/45

Step-by-step explanation:

We know the chances of a blue marble is 4/10 so thats a first

The chances of a green marble WITHOUT the blue marble being put back is 2/9

So you multiply the two fractions

2/9*4/10

you’ll get 8/90 or simplified

4/45

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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
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\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

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