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vitfil [10]
3 years ago
9

Fill the 2 letter bellowh_gs and k_sses​

Chemistry
1 answer:
guajiro [1.7K]3 years ago
5 0
H U gs and k I sses!!! Lol
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Kinetic or potential energy.
Irina18 [472]

Answer:

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion.

4 0
3 years ago
Read 2 more answers
In a mixture of He, O, and N, gases He exerts a partial pressure of 15.22 mm Hg and
gayaneshka [121]

Answer:

P(N)  = 38.48 mmHg

Explanation:

Given data:

Partial pressure of He = 15.22 mmHg

Partial pressure of O = 35.21 mmHg

Partial pressure of N = ?

Total pressure = 88.91 mmHg

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = P(He) + P(O) + P(N)

88.91 mmHg = 15.22 mmHg + 35.21 mmHg + P(N)

88.91 mmHg = 50.43 mmHg + P(N)

P(N)  = 88.91 mmHg  - 50.43 mmHg

P(N)  = 38.48 mmHg

7 0
3 years ago
What is the relationship between.chemicals and cancer ?
timama [110]

Answer:

The relationship is like asbestos and lung cancer or benzene and leukemia because cause and effect.

Explanation:

Chemicals cause Cancer

Nicotine is chemicals so when people smoke JUULS or anything else that's associated with chemicals it causes cancer.

5 0
3 years ago
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150 ml of 0.1 m naoh is added to 200 ml of 0.1 m formic acid, and water is added to give a final volume of 1 l. what is the ph o
N76 [4]

Number of moles of NaOH = V(NaOH) * M(NaOH)= 0.150 L * 0.1 moles/L = 0.015 moles

Number of moles of formic acid, HCOOH = V(HCOOH) * M(HCOOH) = 0.200 L * 0.1 moles/L = 0.020 moles

Here, the limiting reagent is NaOH

The reaction is represented as:

HCOOH + NaOH ↔HCOONa + H2O

Moles of HCOONa formed = Moles of the limiting reagent, NaOH = 0.015 moles

Moles of HCOOH remaining = 0.020-0.015 = 0.005 moles

Total final volume is given as 1 L

Therefore: [HCOOH] = 0.005 moles/1 L = 0.005 M

[HCOONa] = 0.015/1 = 0.015 M

pKa of HCOOH = 3.74

As per Henderson-Hasselbalch equation

pH = pka + log[HCOONa]/[HCOOH] = 3.74+log[0.015/0.005] = 4.22

Therefore, pH of the final solution = 4.22


                       


3 0
3 years ago
How many moles are in 5.5 x 10-23 molecules of H2O
masha68 [24]

Answer:

0.914moles

Explanation:

The number of moles in a substance can be got by dividing the number of atoms/molecules/particles by Avagadro's constant (6.02 × 10^23).

That is;

number of moles (n) = number of atom (nA) ÷ 6.02 × 10^23

According to this question, there are 5.5 x 10-23 molecules of H2O

n = 5.5 x 10^23 ÷ 6.02 × 10^23

n = 0.914 × 10^(23-23)

n = 0.914 × 10^0

n = 0.914 × 1

n = 0.914moles

6 0
3 years ago
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