Answer:
Kc of reaction is 20.
Explanation:
The two proteins are X and Y.
The [X] = 1mM
[Y]=1mM
At equilibrium, [X] = 0.2mM [Y] = 0.2mM
we know that equilibrium constant is:
Kc=![\frac{[Products]}{[Reactants]}=\frac{[XY]}{[X][Y]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BProducts%5D%7D%7B%5BReactants%5D%7D%3D%5Cfrac%7B%5BXY%5D%7D%7B%5BX%5D%5BY%5D%7D)
[XY]= 1-0.20=0.80 mM
putting values:
Kc=
First, we write the half equations for the reduction of the chemical species present:
Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V
In order to determine the potential of the cell, we find the difference between the two values. For this:
E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V
The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
Answer:
b)15.0°C
Explanation:
Specific Heat of Water=4.2 J/g°C
This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.
∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.
80×4.2 J=336 J
Total Energy Provided=1680 J
The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}
Temperature increase=
=5°C
Initial Temperature =10°C
Final Temperature=Initial + Increase in Temperature
=10+5=15°C
Answer:
when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.
Ca(OH)2+ CO2------ CaCO3
when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.
CaCO3+CO2------ Ca(HCO3)