Carbon dioxide can be the cause of burning carbon dioxide and a stove it depends on the heat of the flame in order for carbon dioxide to become carbon monoxide
sorry hope that helps though
<span> </span><span>1. Alcohol(other)
3. Acid
5. Salt
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The answer is nonmetal. good luck and give thanks :)
Answer:
Group 4A (or IVA) of the periodic table includes the nonmetal carbon (C), the metalloids silicon (Si) and germanium (Ge), the metals tin (Sn) and lead (Pb), and the yet-unnamed artificially-produced element ununquadium (Uuq).
The Group 4A elements have four valence electrons in their highest-energy orbitals (ns2np2). Carbon and silicon can form ionic compounds by gaining four electrons, forming the carbide anion (C4-) and silicide anion (Si4-), but they more frequently form compounds through covalent bonding. Tin and lead can lose either their outermost p electrons to form 2+ charges (Sn2+, the stannous ion, and Pb2+, the plumbous ion) or their outermost s and p electrons to form 4+ charges (Sn4+, the stannic ion, and Pb4+, the plumbic ion).
Carbon (C, Z=6).
Carbon is most familiar as a black solid is graphite, coal, and charcoal, or as the hard, crystalline diamond form. The name is derived from the Latin word for charcoal, carbo. It is found in the Earth's crust at a concentration of 480 ppm, making it the 15th most abundant element. It is found in form of calcium carbonate, CaCO3, in minerals such as limestone, marble, and dolomite (a mixture of calcium and
Explanation:
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Answer:
M of MgCl₂ = 1.65 × 10⁻⁶ M
M of Mg²⁺ = 1.65 × 10⁻⁶ M
M of Cl⁻ = 3.30 × 10⁻⁶ M
Explanation:
1) MgCl₂
Molarity = number of moles of solute / volume of solution in liters, M = n / V
n = mass in grams / molar mass
molar mass of MgCl₂ = 24.305 g/mol + 2(35.543 g/mol) = 95.211 g/mol
n = 2.75 × 10⁻⁴ g / 95.211 g/mol = 2.89×10⁻³ moles
⇒ M = n / V = 2.89×10⁻³ moles / 1.75 l = 1.65 × 10⁻⁶ M
2) Mg²⁺ and Cl⁻
Those are the ions in solution.
You assume 100% dissociation of the ionic compound (strong electrolyte).
Then the equation is: MgCl₂ → Mg²⁺ + 2Cl⁻
That means that 1 mol of MgCl₂ produces 1 mol of Mg²⁺ and 2 moles of Cl⁻.
That yields the same molarity concentration of Mg²⁺ , while the molarity concentration of Cl⁻ is the double.
So, the results are:
M of MgCl₂ = 1.65 × 10⁻⁶ M
M of Mg²⁺ = 1.65 × 10⁻⁶ M
M of Cl⁻ = 3.30 × 10⁻⁶ M