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3 years ago

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Describe when an ionic compound can conduct electricity

1 answer:

givi [52]3 years ago

7 0

They cannot move to conduct the electric current. But when an ionic compound melts, the charged ions are free to move. Molten ionic compounds do conduct electricity. When a crystal of an ionic compound dissolves in water, the ions separate.

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is it true that Einstein's equation E=mc2 states that matter can be converted to energy. This is an exception to the Law of Cons

bagirrra123 [75]

The famous formula E=mc^2 really says that mass and energy are the same thing, but measured in different units. So the separate laws of conservation- one for mass and the other for energy- are now merged into one law.

Einstein's theory of special relativity (1905) shows that matter (as mass) and energy can be converted into each other according to the famous equation E = mc2, where E is energy, m is mass, and c is the speed of light.

<em>Hope</em><em> </em><em>It</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

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Whats minimum temperature for scrabble eggs

Sonbull [250]

Answer:

of 160° F. Scrambled eggs need to be cooked until firm throughout with no visible liquid egg remaining.

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Alice and Marge are studying the properties of matter. The girls cut some silver-colored magnesium sheets into 3-inch long strip

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<span>B) Magnesium reacts in acids</span>

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Which chemical formula corresponds to this structural formula?

lys-0071 [83]

I think the answer is choice D

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Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

a)

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

b)

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

c)

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

d)

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

3 0

3 years ago