Answer:
Mass = 0.00541 g
Explanation:
We will convert the larger given values in to smaller by rounding these figures.
Given data:
Mass of zinc sulfide = 43 g
Mass of oxygen = 44.2 g
Mass of zinc oxide = ?
Solution:
Chemical equation:
2ZnS + 3O₂ → 2ZnO + 3SO₂
Number of moles of ZnS:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 43 g/ 97.5 g/mol
Number of moles = 0.44 mol
Number of moles of Oxygen:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 44.2 g/ 32 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.
ZnS : ZnO
2 : 2
0.44 : 0.44
O₂ : ZnO
3 : 2
1.4 : 2/3×1.4 =0.93
The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.
Mass of zinc oxide:
Mass = number of moles / molar mass
Mass = 0.44 mol / 81.38 g/mol
Mass = 0.00541 g
Answer:
Explanation:
Oxidation:
1) Oxidation involve the removal of electrons.
2) Oxidation occur when oxidation state of atom of an element is increased.
Reduction:
1) Reduction involve the gain of electron.
2) Reduction is occur when number of electrons increased in an atom and oxidation state decreased.
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O
The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
The most comprehensive definition is 2nd definition which involves the increase or decrease in oxidation state.
Answer:
Concentration of solution B is
Explanation:
Solution A: Total volume of solution A = (9.00+1.00) mL = 10.00 mL
According to law of dilution,
where and are initial and final concentration respectively. and are initial and final volume respectively.
Here = , = 1.00 mL, = 10.00 mL
So, =
So, concentration of solution A =
Solution B: Total volume of solution B = (2.00+8.00) mL = 10.00 mL
Similarly as above, =
So, concentration of solution B =
Explanation:
Hope this helps:)
The answer is 73.71%. Hope I helped plus mark as brailiest ^-^
Answer:
*result with sodium hydroxide: white ppt of Zn(OH)2
*excess sodium hydroxide: Precipitate dissolves to form a COLOURLESS solution
*Result with Aqueous ammonia: White ppt of Zn(OH)2
*excess aqueous ammonia: Precipitate dissolves to form a COLOURLESS solution
