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stira [4]
2 years ago
7

42,000 mL is equal to L

Chemistry
1 answer:
Goshia [24]2 years ago
3 0

1000ml = 1l

42000ml = 42l

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A certain first-order reaction has a rate constant of 2.15×10−2 s−1 at 20 ∘C. What is the value of k at 55 ∘C if Ea = 72.0 kJ/mo
adell [148]

Answer:

k_2=0.504s^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the rate constant at 55 °C by using the temperature-variable version of the Arrhenius equation:

ln(\frac{k_2}{k_1} )=-\frac{Ea}{R}(\frac{1}{T_2} -\frac{1}{T_1} )

Thus, we plug in the temperatures, activation energy and universal constant of gases in consistent units to obtain:

ln(\frac{k_2}{0.0215s^{-1}} )=-\frac{72000\frac{J}{mol}}{8.3145\frac{J}{mol*K}}(\frac{1}{55+273} -\frac{1}{20+273} ) \\\\ln(\frac{k_2}{0.0215s^{-1}} )=3.154\\\\k_2=0.0215s^{-1}exp(3.154)\\\\k_2=0.504s^{-1}

Regards!

3 0
3 years ago
The density (g/L) of CO2 gas at STP ( 273 K, 1.00 atm) is
Triss [41]

The density : 1.96 g/L

<h3>Further explanation</h3>

Ideal gas Law

Pv=nRT

where  

P = pressure, atm , N/m²  

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)  

T = temperature, Kelvin  

so for density,

MW CO₂ = 44 g/mol

\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 44}{0.082\times 273}\\\\\rho=1.96~g/L

3 0
2 years ago
Weeks and how much money, in dollars, Jamal deposits into the savings account.
pantera1 [17]

An

196 becase we all rice

Explanation:

8 0
3 years ago
What is the percentage composition of each element in hydrogen peroxide, H2O2?
Degger [83]

Answer:

The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).

Explanation:

Step 1: Data given

Molar mass of H = 1.0 g/mol

Molar mass of O = 16 g/mol

Molar mass of H2O2 = 2*1.0 + 2*16 = 34.0 g/mol

Step 2: Calculate % hydrogen

% Hydrogen = ((2*1.0) / 34.0) * 100 %

% hydrogen = 5.88 %

Step 3: Calculate % oxygen

% Oxygen = ((2*16)/34)

% oxygen = 94.12 %

We can control this by the following equation

100 % - 5.88 % = 94.12 %

The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).

8 0
3 years ago
Read 2 more answers
Most ionic compounds tend to be classified as Select one:
Dovator [93]
Most ions tend to be D. Salts. Hope this helps!
5 0
3 years ago
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