$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3$

5 0

3 years ago

Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!

kvasek [131]

Hello,

Answer D

x²/25+y²/16=1

5 0

3 years ago

Write an explicit formula for then th an. term of the sequence 45, 15,5. ....

7nadin3 [17]

Answer:

The sequence above is a geometric sequence

For an nth in a geometric sequence

$u(n) = a {r}^{n - 1}$

where n is the number of terms

a is the first term

r is the common ratio

From the question

a = 45

r = 15 / 45

The explicit formula for the sequence is

U(n) = 45(1/3)^n-1

Hope this helps you

7 0

3 years ago