Add all of them and them subtract by the value
<span>If lim(x->3) f(x)=7, then </span><span>f(3) = 7.</span>
The awnser is 1000 because 60 miutes in an hour, 50 mouse traps every half hour so 100 mouse traps an hour multiply that by 10 and you get 1000, i think.
Answer:
Step-by-step explanation:
Let the no of cars be x and no of buses be y.
x + y = 60 -> y = 60 - x
6x + 30y = 600
with the available equations let us calculate the values of x and y.
6x + 30 * (60-x) = 600
6x + 1800 - 30x = 600
24x = 1200
x cars = 50
y buses = 10
maximum profit = 50 * 2.5 + 10 * 7.5 = $200
Answer:
mmmm cnt get to it srry
Step-by-step explanation:
