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MAVERICK [17]
3 years ago
15

The engineer of a train traveling at 30 m/sec sees a cow on the tracks. He applies the brakes and causes the train to accelerate

at -1.5 m/sec2. How far will the train travel in 4 seconds after applying the brakes? Do your work in your notebook, type in your final answer and upload a picture of the work as your solution to the problem.
Physics
1 answer:
sineoko [7]3 years ago
8 0

Answer:The train travels 105 meters after applying the brakes

Explanation:If he decelerates 1.5 every minute, then he went from 28,5 m/s, to 27.0 m/s, to 25.5 m/s, to 24.0 m/s, after 4 seconds. Add all this together and youll get 105 meters moved in 4 seconds after he hit the brakes, I dont have a notebook on me though sorry :/

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If the system is operated on mars, through what distance would the 18.0-kg mass have to fall to give the same amount of kinetic
-Dominant- [34]
The previous part of the exercise says:
"<span>Engineers are designing a system by which a falling mass m imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum. There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on Earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s². In the Earth tests, when m is set to 18.0 kg and allowed to fall through 5.50 m, it gives 300.0 J of kinetic energy to the drum."

Since Kearth = Kmars, we have, for conservation of energy, that also the potential energies must be equal:
Uearth = Umars

which means:
m </span>· gearth · hearth = m · gmars <span>· hmars

we can solve for hmars:
hmars = (gearth / gmars) </span>· hearth
           = (9.8 / 3.71) · 5.50
           = 14.53m

Therefore, the correct answer will be: the mass would have to fall from an height of 14.53m.

5 0
3 years ago
What is the direction of the third force that would cause the box to remain stationary on the ramp ?
krek1111 [17]

An arrow pointing from the bottom of the ramp to the top, I assume it would be friction.

6 0
3 years ago
Read 2 more answers
A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8 coulombs. What is the electric field at t
Alborosie
The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge. 

E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.

So E=(k*q)/r² 

When we input the numbers we get that electric field E of a point chage q is:

E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B. 
6 0
3 years ago
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A surface will be an equipotential surface if (there may be more than one correct choice).A. the electric field is zero at all p
aev [14]

Answer:

c. A, C

Explanation:

On equi-potential surface, fields are equal in magnitude at all points . If field is zero at all points , they will be equal so first option is correct.

Field is perpendicular to  equipotential surface at all points.

6 0
3 years ago
What is the word for a connected web of brain cells whose bonds grow stronger the more you use them?
soldier1979 [14.2K]

Answer:

This question appear incomplete

Explanation:

This question appear incomplete because of the lack of options. However, a connected web of cells is generally referred to as the tissue. These cells are joined together by cell-cell adhesion (a form of bond) to form the tissue. The type of tissue being referred to here is the nervous tissue as this is the type of tissue present in the nervous system (including the central nervous system of which the brain is a part of).

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