The body continuously tries to maintain homeostasis. Therefore, the digestive system eliminate waste from your body along as providing the body with the nutrients needed. It balances out your every meal.
The volume of a cylinder is given by the formula v=pi r^2h, where r is the radius of the cylinder and h is the height.
<h3>What Does a Cylinder's Surface Area Look Like?</h3>
The overall area or region that the surface of a cylinder covers is referred to as its surface area. A cylinder's total surface area includes both the area of the curved surface and the area of the two flat surfaces because there are two flat surfaces and one curved surface. A cylinder's surface area is measured in square units like m2, in2, cm2, yd2, etc.
<h3>What is the cylinder's total surface area?</h3>
The sum of the curved surface areas makes up the cylinder's overall surface area.
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Answer:
High pressure inside the giant planet
Explanation:
As we move in the interior of the giant planet, the pressure and temperature in the interior of the planet increases. Since, the giant planets have hardly any solid surface and thus they are mostly constituted of atmosphere.
Also, the gravitational forces keep even the lightest of the matter bound in it contributing to the large mass of the planet.
If we look at the order of the magnitude of the temperature of these giant planets than nothing should be able to stay in liquid form but as the depth of the planet increases with the increase in temperature, pressure also increases which keeps the particle of the matter in compressed form.
Thus even at such high order of magnitude water is still found in liquid state in the interior of the planet.
Answer:
b. 
Explanation:
As we know that the electric field due to infinite line charge is given as
here we can find potential difference between two points using the relation
now we have
now we have
now plug in all values in it
now we know by energy conservation
Answer:
The magnitude of the electric field is 1.124 X 10⁷ N/C
Explanation:
Magnitude of electric field is given as;
where;
E is the magnitude of the electric field, N/C
q is the point charge, C
k is coulomb's constant, Nm²/C²
r is the distance of the point charge, m
Given;
q = 5mC = 5×10⁻³ C
r = 2m
k = 8.99 × 10⁹ Nm²/C²
Substitute these values and solve for magnitude of electric field E
Therefore, the magnitude of the electric field is 1.124 X 10⁷ N/C
