Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N(
)
Now, the z score probability distribution is given by;
Z = 
~ N(0,1)
where, 
= mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P( < 
) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
<span>A. Find the complement of the angle shown
90 - 52 = 38
</span><span>B. Find the supplement of the angle shown.
180 - 52 = 128
hope that helps</span>
You can rule out A and C 6/6 makes 1 so that cancels so your answer is D
D . a pod of humpback whales ( sorry if it’s wrong )
(a) The statement of owner's equity for Year 1 is $26,920
(b) The statement of owner's equity for Year 2 is $52,720
(a) Preparation of the statement of owner's equity for Year 1 at its December 31 year end.
JARVIS statement of owner's equity for year ended December 31 Year 1
Owner investment $12,400
Add Net income $ 33,600
Less Jarvis, Withdrawals ($ 19,080)
Statement of owner's equity for Year 1 $26,920
(b) Preparation of the statement of owner's equity for Year 2 at its December 31 year end.
JARVIS statement of owner's equity for year ended December 31 Year 2
Owner investment $12,400
Add Net income $ 56,000
Less Jarvis, Withdrawals $ 15,680
Statement of owner's equity for Year 2 $52,720
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