answer
When an electron temporarily occupies an energy state greater than its ground state, it is in an excited state. An electron can become excited if it is given extra energy, such as if it absorbs a photon, or packet of light, or collides with a nearby atom or particle
Answer:24 kilometers
Explanation:Density divided by time
Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%
690 Kelvin is the boiling point of this compound.
Explanation:
Enthalpy is the sum of internal energy and the product of pressure and volume that is how much energy is in the substance.
Entropy is the measurement of randomness and measure of thermal energy per unit of temperature.
ΔH vap of compound is 46.55 kJ⋅ mol− or J.MOL-1
ΔS vap is 67.37 J⋅mol−1⋅K−1.
The boiling point or temperature can be calculated by the formula:
T=
T =
= 690 Kelvin
The boiling point is the temperature when atmospheric temperature gets equal to
<span>Soln:
•t: in min
•Q(t): quantity of dye in the tank at time t
•r in= 0: rate of dye poured into the tank per min. Since it is fresh water, so it
is zero.
•r out= density of dye×rate of fluid =Q/900×9: rate of dye flowing out.
•Q(0) = 1×900 g: initial amount of dye in the tank.
•{dQ/dt=rin-rout= 0-Q100 Q(0) = 900g•Q(t)=Ce-1/100t
•Q(0) = 900, C= 900, Q(t) = 900e-1/100t
•Q(t) = 0.01·Q(0), Q(0)e-1/100t= 0.01×Q(0),-t100= ln 0.01, t= 460min</span>