Answer:
Al: 3
S: 6
Explanation:
Al is in Group III. This means that it has 3 valence electrons.
S is in Group VI. This means that it has 6 valence electrons.
I hope this helps :)
Since there are no given data for us to solve this problem, I will explain what a Standard Reduction Potential is. For example, if a student had an experiment and he wanted to know what is the most efficient and powerful
redox reaction involving an uncommon combination of chemicals. The student would
most likely record information in the Standard Reduction Potential that showed the voltage generated by the
reaction in Aqueous Solution at 25 degrees Celsius and 1 atmosphere. This is a list
of half reaction of ions in the solution at standard temperature and pressure.
The krypton-83 isotopes below is formed when rubidium-83 undergoes electron capture.
What is isotopes?
isotopes are defined as atoms with a constant number of protons but a variable number of neutrons. Despite having different masses and hence having different physical qualities, they have nearly identical chemical properties.
What is stable nuclide?
Since stable nuclides are not radioactive, they do not spontaneously decay into radioactive elements as happens with radionuclides. They are commonly referred to as stable isotopes when such nuclides are discussed in connection to particular elements.
The electron capture process will turn rubidium-83 into krypton-83. When a proton in the nucleus catches an inner electron and creates a neutron, this process is known as electron capture.
Therefore, krypton-83 isotopes below is formed when rubidium-83 undergoes electron capture.
Learn more about isotopes from the given link.
brainly.com/question/364529
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Answer:
11.2 grams CaO
Explanation:
It appears that substance X may be calcium carbonate: CaCO3
CaCO3 can be thermally decomposed to CO2 and CaO in the following balanced reaction:
CaCO3(s) ⇒ CaO(s) + CO2(g) (with applied heat, 840°C)
The molar ratio between the product, CaO, and the reactant, CaCO3, is 1:1. If we start with 1 mole CaCO3, we should produce 1 mole of CaO.
We have 20.0 grams of substance X, which we'll label CaCO3. Calculate the moles of CaCO3 by using its molar mass of 100.1 grams/mole.
20.0 grams/(100.1 grams/mole) = 0.1998 or 0.200 moles of CaCO3.
This should produce, with a molar ratio of 1 to 1, 0.200 moles of CaO
Convert this to grams CaO by multiply by it's molar mass of 56.1 g/mole:
(0.200 moles)*(56.1 g/mole) = 11.2 grams CaO. Any less, then blame it on your lab partner. But don't try taking credit if you have more than 11.2 grams. Scraping debri off the counter into the beaker doesn't count.
