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Nat2105 [25]
3 years ago
8

Sample of neon has a volume of 75.8 L at STP? How many miles are present

Chemistry
1 answer:
harina [27]3 years ago
3 0
1 mole ---------- 22.4 L at ( STP)
? moles -------- 75.8 L

75.8 x 1 / 22.4 => 3.3839 L

hope this helps!
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How can the amount of electrical energy produced be less than the initial radiant energy from the sun?
VLD [36.1K]

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3 0
2 years ago
A cylindrical container of garlic powder has a height of 9 cm and 1.2 times the radius of another cylindrical container of the s
andreev551 [17]
To solve this you need to find the radius of the bigger cylinder so you have to solve the equation 36π=r^{2}π(9). When you solve it you end up with a radius of 2 in which you multiply by 1.2 which gives you the radius of the new cylinder which is 2.4. With the new radius you simply find the volume of the bigger cylinder which is 51.94πcm^{3}.
5 0
3 years ago
Concerning the 10.0 mL of 0.50 M NaCl to 100 mL of solution: When a solution is diluted, does it change the number of moles diss
Mars2501 [29]

No, the dilution does not change the number of moles dissolved

Explanation:

We can see that,

The molarity of the solution was 0.50 M

The volume of the solution is 10 ml.

No of moles of the solute was= volume * concentration

                                                   = 10 X 10^-3* 0.50

                                                     = 5*10^-3 moles

When the solution is diluted from 10 ml to 100ml, the molarity or concentration  changes but number of moles remains constant.

The molarity of 100 ml solution will be

c=n/V

  = 5*10^-3*/100*10^-3

  = 0.05

  when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M

8 0
3 years ago
Read 2 more answers
2C4H10+13O2--&gt;8CO2+10H2O Using the predicted and balanced equation, How many Liters of CO2 can be produced from 150 grams of
Anna11 [10]

Answer:  233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} C_4H_{10}=\frac{150g}{58g/mol}=2.59moles

The balanced chemical equation is:

2C_4H_{10}+13O_2(g)\rightarrow 8CO_2+10H_2O  

According to stoichiometry :

2 moles of C_4H_{10} produce =  8 moles of CO_2

Thus 2.59 moles of C_4H_{10} will produce=\frac{8}{2}\times 2.59=10.4moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=10.4moles\times 22.4mol/L=233L

Thus 233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

8 0
3 years ago
PLEASE PEOPLE I NEED HELP PLEASE IF YOU SEE THIS HELP ME ! :,(
mr Goodwill [35]

Answer: 5.5 7.5 102

Explanation: using the equation above you can get these %s

8 0
2 years ago
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