Question

How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points

Answer 1

The heat lost is $-7.32*10^-^5J$

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

Heat Transfer

This is the heat transferred from a body of higher temperature to a body of lower temperature.

$Q = mc(\delta)T$

• Q = Heat Transfer
• m = mass = 1277g
• ΔT  = change in temperature

$\delta T = (400 - 273) - (263 - 273) = \\ \delta T = T_2 - T_1\\ \delta T = -10 - 127\\ \delta T = -137^0C$

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

$Q = mc\delta T\\ Q = 1277 * 4.186 * -137\\ Q = -732336.514J$

The heat loss is approximately $-7.32*10^-^5J$

Learn more on heat transfer here;

brainly.com/question/16055406