2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)
The molar ratio between NaCN : HCN is 2:2 or 1:1
Mass of HCN = 16.7 g
Molar mass of HCN = 1 + 12 + 14 = 27 g/mol
Molar mass of NaCN = 49 g/mol
Therefore, the mass of NaCN is
16.7 g of HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN
Therefore, 30.3 grams of NaCN gives the lethal dose in the room.
The answer is
<span>HF + H2O <--> H3O(+) + F(-)
</span>
<span>HF + H2O gives H3O(+) + F(-)
and </span>
H3O(+) + F(-)
gives <span>HF + H2O
it is a reciprocal reacation, so </span>
<span>reactions are both reactants and products </span>
The picture isn’t loading smh
