Answer:
See Explanation
Explanation:
Positional Energy for electron as function of principle energy level (n)
=> Eₙ = -A/n²; A = 2.18x10⁻¹⁸J
Positional Energy for electron in n=2 => E₂ = -2.18x10⁻¹⁸/(2)² = -5.45x10⁻¹⁹J
Positional Energy for electron in n=3 => E₃ = -2.18x10⁻¹⁸/(3)² = -2.42x10⁻¹⁹J
ΔE(n=3→2) = -5.45x10⁻¹⁹J - (-2.42x10⁻¹⁹J) = -3.03x10⁻¹⁹J
Well even though im not giving you the whole answer, Im going to tell you what to do in order for you to do it. The main thing you need to do is to determine the delta H and delta S for the reaction.<span>Then subtract the reactants from the products.
On eexample of this is: </span><span>Delta H = (-634.9(CaO)+-393.5(CO2)) - (-1207.6 (CaCO3)) = 179.2 kJ
</span><span>Do the same thing for Delta S but make sure you use the correct units. Delta S is in Joules so you may need to convert. Once you have those values, plug into the equation
</span><span>Delta G= Delta H - T * Delta S
</span>And you will get your result
hope this is very useful for you
Answer:
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Answer : The correct option is, (c) pyramidal
Explanation :
As we are given that a molecule in which the central atom forms three single bonds and has one lone pair that means the central metal atom has 3 bond pairs and 1 lone pair of electrons.
There are total 4 electron pairs. So, the hybridization will be 
and the electronic geometry of the molecule will be tetrahedral.
But as there are three atoms or bonds around the central atom and the fourth position occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be pyramidal.
Hence, correct option is, (c) pyramidal
