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stich3 [128]
3 years ago
15

One-step constrained-volume synthesis of silver decorated polymer colloids with antimicrobial and sensing properties,

Chemistry
1 answer:
Anarel [89]3 years ago
5 0
It would be the thurd
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Which type of material incorporates a variety of substances to enhance desired properties such as strength and flexibility?
Blizzard [7]

Answer:

its a polymer

Explanation:

4 0
3 years ago
Consider the following reactions:
Advocard [28]
What’s the question cuz I’m confused lol
5 0
3 years ago
What are the concentrations of A , A, B , B, and C C at equilibrium if, at the beginning of the reaction, their concentrations a
Elenna [48]

The question is incomplete, here is the complete question:

A reaction

A+B\rightleftharpoons C

has a standard free-energy change of -4.88 kJ/mol at 25°C

What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30 M, 0.40 M and 0 M respectively?

<u>Answer:</u> The equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

<u>Explanation:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_c

where,

\Delta G^o = Standard Gibbs free energy = -4.88 kJ/mol = -4880 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_c = equilibrium constant of the reaction

Putting values in above equation, we get:

-4880J/mol=-(8.3145J/Kmol)\times 298K\times \ln K_c\\\\K_c=7.17

We are given:

Initial concentration of A = 0.30 M

Initial concentration of B = 0.40 M

Initial concentration of C = 0 M

The chemical reaction follows:

                               A+B\rightleftharpoons C

<u>Initial:</u>                 0.30  0.40      0

<u>At eqllm:</u>         0.30-x   0.40-x    x

The expression of equilibrium constant for the above reaction follows:

K_c=\frac{[C]}{[A][B]}

We are given:

K_c=7.17

Putting values in above equation, we get:

7.17=\frac{x}{(0.30-x)\times (0.40-x)}\\\\x=0.183,0.657

Neglecting the value of x = 0.657, because change cannot be greater than the initial concentration

So, equilibrium concentration of A = (0.30-x)=(0.30-0.183)=0.117M

Equilibrium concentration of B = (0.40-x)=(0.40-0.183)=0.217M

Equilibrium concentration of C = x=0.183M

Hence, the equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

5 0
3 years ago
What is the mass of 3.95 l of methane gas at 0.870 atm and 35.0 degrees celsius?
dalvyx [7]

Answer:

2.174 gm

Explanation:

PV = nRT       n = number of moles

                       R = gas constant = .082057 L-atm/(K-mol)

                           T must be in units of K

.870 (3.95) = n (.082057)(35+273.15)    

   solve for n = .1359 moles

Methane mole weight (CH4) = 16 gm / mole

.1359 moles  *  16 gm/mole = 2.174 gm

5 0
2 years ago
How many cm are in 7 km?
nikklg [1K]

Answer:

70000 cm in 7km

Explanation:

There are 1000 m and 100 cm in 1 m in 1 km, so to find how many cm are in 7 km you need to do 10000 x 7.  You get 70000

Have a nice day!

5 0
3 years ago
Read 2 more answers
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