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rosijanka [135]
3 years ago
6

What four factors account for the abundance of carbon compounds

Chemistry
2 answers:
Blizzard [7]3 years ago
6 0
Dunno about four factors, but one is that carbon will form four bonds (some are single, some double, some triple). It can bond to other carbon atoms to create structures of almost any shape.
AVprozaik [17]3 years ago
4 0
I don't know sorry I wish I could help
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A lab group was supposed to make mL of a acid solution by mixing a solution, a solution, and a solution. However, the solution w
MissTica

Question: The question is not complete. Find below the complete question and the answer.

Alab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? mL

Volume of 20% solution= ?

Volume of 26% solution = ?

Volume of 42% solution= ?   Round to the nearest whole number ml

Answer:

Volume of 20% solution= 3 mL

Volume of 26% solution = 1 mL

Volume of 42% solution= 10 mL

Explanation:

Find attached of the calculations.

3 0
3 years ago
Which pair of elements is most apt to form an ionic compound with each other?
sweet [91]
Ionic compounds are compounds that are formed together by a cation and an anion. A cation is an ion with a positive charge. For example, Na+ and Ca2+. An ion has a negative charge, like Cl- and OH-. There is a greater chance of forming an ionic compound when they have a great difference in electronegativity, the ability to attract electrons toward itself. In the periodic table, elements that are opposite to each other, more likely found in opposite sides, would be more apt to form an ionic compound. Example would be NaCl and CaCl2 or Ca(OH)2.
7 0
3 years ago
In this experiment you’ll be grabbing the relationship between mass and volume you’ll be placing the volume on the X axis and th
Contact [7]

The mass and volume has direct proportional to each other.

<h3>What is the relationship between mass and volume?</h3>

The volume of the object is directly proportional to its mass which means that if the volume increases the mass of the object increases also increase and vice versa. Due to this direct relationship, the line of regression will go straight between X and Y axis.

So we can conclude that mass and volume has direct proportional to each other.

Learn more about volume here: brainly.com/question/1972490

#SPJ1

6 0
2 years ago
I really need help please
Greeley [361]

Answer:

I think it's B

hope this helps

5 0
3 years ago
one reaction that produces hydrogen gas can be represented by the unbalanced chemical equation Mg(s)+HCI(aq) -&gt; MgCI(aq)+H2(g
Sonbull [250]
<h3>Answer:</h3>

128 g HCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Reaction Mole Ratios
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg (s) + HCl (aq) → MgCl (aq) + H₂ (g)

↓

[RxN - Balanced] 2Mg (s) + 2HCl (aq) → 2MgCl (aq) + H₂ (g)

[Given] 3.25 mol Mg

[Solve] x g HCl

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol HCl

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

<u>Step 3: Stoich</u>

  1. [S - DA] Set up:                                                                                                 \displaystyle 3.25 \ mol \ Mg(\frac{2 \ mol \ HCl}{2 \ mol \ Mg})(\frac{36.46 \ g \ HCl}{1 \ mol \ HCl})
  2. [S - DA] Multiply/Divide [Cancel out units]:                                                    \displaystyle 127.61 \ g \ HCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

127.61 g HCl ≈ 128 g HCl

3 0
3 years ago
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