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Ilya [14]
2 years ago
8

In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses. what happens in

each half cell? the half cell in which the electrode gains electrons is where occurs, and the half cell in which the electrode loses electrons is where occurs.
Chemistry
1 answer:
Sidana [21]2 years ago
7 0

The half cell in which the electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.

<h3><u>What is a Galvanic cell ?</u></h3>

Voltaic or galvanic cells are electrochemical devices that use spontaneous oxidation-reduction events to generate electricity. In order to balance the overall equation and highlight the actual chemical changes, it is frequently advantageous to divide the oxidation-reduction reactions into half-reactions while constructing the equations.

Two half-cells make up most electrochemical cells. The half-cells allow electricity to pass via an external wire by separating the oxidation half-reaction from the reduction half-reaction.

<h3><u>Oxidation:</u></h3>

The anode is located in one half-cell, which is often shown on the left side of a figure. On the anode, oxidation takes place. In the opposite half-cell, the anode and cathode are linked.

<h3><u>Reduction:</u></h3>

The second half-cell, cathode, which is frequently displayed on a figure's right side. The cathode is where reduction happens. The circuit is completed and current can flow by adding a salt bridge.

To know more about processes in Galvanic cell, refer to:

brainly.com/question/13031093

#SPJ4

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lorasvet [3.4K]

Answer:

\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

  • K: 39.098 g/mol
  • C: 12.011 g/mol
  • O: 15.999 g/mol

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

  • 2(39.098 g/mol) + 3(15.999 g/mol) + 12.011 g/mol= 138.204 g/mol

2. Convert Moles to Grams

Use the molar mass as a fraction.

\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

Multiply by the given number of moles: 6.2

6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

6.2  *\frac {138.204 \ g \ K_2CO_3}{1 }

6.2  * {138.204 \ g \ K_2CO_3}

856.8648 \ g \ K_2CO_3

There are <u>856.8648 grams</u> of potassium carbonate in 6.2 moles.

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Question 6<br> Which element is a noble gas?<br> Te<br> Xe<br> I
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Answer:

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You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.
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The question requires us to use the dilution formula M_iV_i=M_fV_f, where M_i and V_i are the stock concentration and volume respectively, then M_f and V_f are the dilute concentration and volume respectively.

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b.M_iV_i=M_fV_f\\\implies V_i= \frac{M_fV_f}{M_i} = \frac{0.20M \times 250ml}{1.5M} = 33.3\ ml

To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.


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