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Maksim231197 [3]
3 years ago
7

What product(s) are formed during the complete combustion reaction that occurs when methane (CH4) and molecular oxygen (O2) reac

t? CO2 and H4 C and H2O CO2 and H2O C(OH)4
Chemistry
1 answer:
Vilka [71]3 years ago
3 0

Answer: CO2 and H2O

Explanation: I already took the test it's right

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As the amount of charge on two objects increases, the strength of the electrical force between the objects
Aleks [24]

Answer:

Increase is the answer

Explanation:

Increase is the answer hopes this helps you

6 0
2 years ago
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A block of pine wood has a mass of 120 g and a volume of 300 cm3. What is the density of wood? (Show your work)
Zielflug [23.3K]

Answer:

The answer is

<h2>0.4 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of wood = 120 g

volume = 300 cm³

So the density of the wood is

density =  \frac{120}{300}  \\  =  \frac{12}{30}  =  \frac{2}{5}

We have the final answer as

<h3>0.4 g/cm³</h3>

Hope this helps you

5 0
3 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
DaniilM [7]
800 joules because it's twice the amount
7 0
3 years ago
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How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

6 0
2 years ago
6. 100 ml of gaseous hydrocarbon consumes 300
mario62 [17]

Answer:

  • <u><em>a. C₂H₄</em></u>

Explanation:

At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).

Hence, the <em>complete combustion reaction</em> that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.

Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).

A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.

<u>a. C₂H₄:</u>

  • C₂H₄ (g) + 3O₂ (g) → 2CO₂(g)  + 2H₂O (g)

Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.

The following analysis just shows that the other options are not right.

<u>b. C₂H₂:</u>

  • 2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g)  + 2H₂O (g)

The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.

<u>с. С₃Н₈</u>

  • C₃H₈ (g) + 5O₂ (g) → 3CO₂(g)  + 4H₂O (g)

The mole ratio is 1 mol C₃H₈ : 5 mol O₂

<u>d. C₂H₆</u>

  • 2C₂H₆ (g) +7 O₂ (g) → 4CO₂(g)  + 6H₂O (g)

The mole ratio is 2 mol C₂H₆ : 7 mol O₂

7 0
3 years ago
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