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Maksim231197 [3]

2 years ago

7

What product(s) are formed during the complete combustion reaction that occurs when methane (CH4) and molecular oxygen (O2) reac

t? CO2 and H4 C and H2O CO2 and H2O C(OH)4

1 answer:

Vilka [71]2 years ago

3 0

Answer: CO2 and H2O

Explanation: I already took the test it's right

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Assume the cup of tea has cooled off faster than the pot of tea. In which liquid would the molecules be moving faster and in whi

OLga [1]

In the pot of tea the molecules would be moving faster than in the cooled cup of tea. As liquid is heated the atoms vibrate faster which increases the distance between them. When heat leaves a substance, the molecules vibrate slower and get closer.

8 0

2 years ago

Read 2 more answers

How have chemists changed our daily lives the most

sladkih [1.3K]

By using what they know to produce new and helpful products

4 0

2 years ago

The 85.2-g sample of the compound x4o10 contains 48.0 g of oxygen atoms. what is the molar mass of element x?

Vedmedyk [2.9K]

X4O10
Let molar mass of X be y
molar mass = 4y + 10 x 16 = 4y+160

so, moles = 85.2 / (4y+160)

Moles of oxygen = 10 x [85.2 / (4y+160) ]
Mass of oxygen = 16 x 10 x [85.2 / (4y+160) ]
which is 48.0

so, 48 = 16 x 10 x [85.2 / (4y+160) ]

Solve the equation to get y.

y = 31

5 0

2 years ago

If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.

Klio2033 [76]

Answer : The final temperature of the mixture is $22.7^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

$(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.3J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol

$m_2$ = mass of water

$\rho_1$ = density of ethanol = 0.789 g/mL

$\rho_2$ = density of water = 1.0 g/mL

$V_1$ = volume of ethanol = 45.0 mL

$V_2$ = volume of water = 45.0 mL

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $9.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get

$(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.7^oC$

Therefore, the final temperature of the mixture is $22.7^oC$

4 0

2 years ago

How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?

Sati [7]

Hello!

The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes

Why?

We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:

$Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\ \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes$

So, 7 ice cubes are required to absorb that amount of heat from the glass of water.

Have a nice day!

3 0

2 years ago