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BigorU [14]
4 years ago
8

A town is designing a rectangular park that will be 600 feet by 1000 feet. A rectangular area of the park for swing sets will be

25 feet by 100 feet. On a scale drawing of the park, the swing set area is 0.5 inch by 2 inches.
What are the dimensions of the park on the scale drawing?
Mathematics
2 answers:
Cerrena [4.2K]4 years ago
7 0
Do length*hight find width and divided by 2
Kay [80]4 years ago
5 0
12by20


is the correct
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Sam's total expenses last month were $1840. What was his total variable cost for last
likoan [24]

Answer:

$1500

Step-by-step explanation:

It is given that

Rent  = $100

Groceries and drinks = $1000

Insurance premiums   = $10

Loan interest payment  =$30

Clothes  = $200

Utilities  = $300

Home security fee  = $200​

Fixed cost are costs that does not vary and variable cost are costs that vary with goods and services.

In the given problem, rent , insurance premiums, loans interest payment ad home security fee are fixed cost.

Groceries and drinks, clothes and utilities are variable cost.

So, total variable cost for last month is

\text{Total variable cost}=\$1000+\$200+\$300=\$1500

Therefore, total variable cost for last month is $1500.

5 0
3 years ago
The number of school buses needed to transport students on a field trip is given by the function
Mashcka [7]

Answer:

Answer is C

I don't know properly

I hope you like it

4 0
3 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
Please help! Will give brainliest!
const2013 [10]
<h3>1.</h3>

The equation in point-slope form:  y - y₁ = m(x - x₁)

slope:  m = -2

point:   (4, -5)   ⇒   x₁ = 4, y₁ = -5

Therefore, the equation of the line in point-slope form:

<h3>y + 5 = -2(x - 4)</h3>

<h3>2.</h3>

The equation in slope-intercept form:   y = mx + b

Parallel lines has the same slope, so:

y = 4x + 2     ⇒    a = 4

If a line passes through the point <em>(x₁, y₁) </em>then the equation y<em>₁</em> = mx<em>₁</em> + b is true.

(4, 6)  ⇒   x₁ = 4, y₁ = 6  

So:   6 = 4·4 + b  ⇒   b = -10

Therefore the equation:  

<h3>y = 4x - 10</h3>

<h3>3.</h3>

a = 3

(-1, 1)  ⇒   x₁ = -1, y₁ = 1  

So:   1 = 3·(-1) + b  ⇒   b = 4

The equation:  

<h3>y = 3x + 4</h3>

<h3>4. </h3>

The product of slopes of perpendicular lines is -1.

2x - 7y = 1    ⇒  7y = -2x + 1   ⇒  y = -²/₇x + ¹/₇

-²/₇×m = -1    ⇒   m = ⁷/₂

(0, -4)  ⇒   x₁ = 0, y₁ = -4  

-4 = ⁷/₂·0 + b   ⇒   b = -4

The equation:

<h3>y = ⁷/₂x - 4</h3>
8 0
3 years ago
Which expression is equivalent to (xy)z?
aleksandr82 [10.1K]
X/yz is the answer I believe
6 0
3 years ago
Read 2 more answers
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