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3 years ago

You put a room temperature metal spoon into a bowl of hot soup. What will happen to

Physics

1 answer:

Semenov [28]3 years ago

7 0

Answer:

the soup will transfer its thermal energy to the spoon

Hope this helps! Can you please mark me brainliest? (also can you guys answer my recent questions? thanks ^^ )

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A ray diagram shows that an object is placed in front of a plane mirror. What are the characteristics of the image produced by t

romanna [79]

Same size as object should be the answer, it is a “plane” mirror

3 0

2 years ago

Read 2 more answers

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$

Bulb B (3 L, 4 atm) - Before opening:

$P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T$

Bulbs A & B (5 L) - After opening:

$P_{C} \cdot (V_{A} + V_{B}) = (n_{A} + n_{B})\cdot R_{u} \cdot T$

After some algebraic manipulation, a formula for final pressure is derived:

$P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}$

And final pressure is obtained:

$P_{C} = \frac{(2\,atm)\cdot (2\,L)+(4\,atm)\cdot(3\,L)}{5\,L}$

$P_{C} = 3.2\, atm$

5 0

2 years ago

Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t

satela [25.4K]

1) At the top, the ball has more potential energy

2) Halfway through the fall, potential energy and kinetic energy are equal

3) Before hitting the ground, the ball has more kinetic energy

4) Potential energy at the top: 784 J

5) Potential energy halfway through the fall: 392 J

6) Kinetic energy halfway through the fall: 392 J

7) KInetic energy before hitting the ground: 784 J

Explanation:

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field. It is given by

$PE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object above the ground

The kinetic energy of an object is the energy possessed by the object due to its motion, and it is given by

$KE=\frac{1}{2}mv^2$

where v is the speed of the object

For the bowling ball in the problem, when it sits on top of the building it has no kinetic energy (because its speed is zero, v = 0), therefore it has more potential energy than kinetic energy.

The total mechanical energy of the ball, which is the sum of the potential and the kinetic energy, is constant during the fall:

$E=PE+KE=const.$

When the ball is at the top, all its energy is potential energy, since the kinetic energy is zero:

$E=PE=mgH$

where H is the initial height.

When the ball is halfway through the fall, the height is H/2, so:

$PE=mg\frac{H}{2}$

which means that the potential energy is now half of the total mechanical energy: but since the total energy must be constant, this means that the kinetic energy is now also half of the total energy. Therefore, potential energy and kinetic energy are equal.

When the ball is just before hitting the ground, the height of the ball is now zero

h = 0

This also means that the potential energy is zero

PE = 0

Therefore, all the energy of the ball is now kinetic energy:

$KE=E$

which means that the kinetic energy is maximum, and therefore it is larger than the potential energy: this is because the ball accelerates during the fall, and therefore its speed is maximum just before hitting the ground.

The potential energy of the ball is given by

$PE=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object above the ground

When the ball sits at the top, we have

m = 2 kg

$g=9.8 m/s^2$

h = 40 m

Therefore, the potential energy is

$PE=(2)(9.8)(40)=784 J$

The potential energy of the ball is given by

$PE=mgh$

where

m = 2 kg is the mass

$g=9.8 m/s^2$ is the acceleration due to gravity

When the ball is halfway through the fall, the height of the ball is

h = 20 m

Therefore, its potential energy is

$PE=(2)(9.8)(20)=392 J$

which is half of the initial potential energy.

The kinetic energy of the ball is given by

$KE=\frac{1}{2}mv^2$

where

m is the mass of the ball

v is its speed

When the ball is halfway through the fall, we have:

m = 2 kg (mass of the ball)

v = 19.8 m/s (speed of the ball)

Therefore, the kinetic energy is

$KE=\frac{1}{2}(2)(19.8)^2=392 J$

Which is equal to the potential energy.

The kinetic energy of the ball just before hitting the ground is

$KE=\frac{1}{2}mv^2$

where in this case,

m = 2 kg is the mass

v = 28 m/s is the speed of the ball

Therefore, kinetic energy is

$KE=\frac{1}{2}(2)(28)^2=784 J$

And we see that the kinetic energy of the ball just before hitting the ground is equal to the potential energy of the ball when it sits at the top: therefore, all the mechanical energy has converted from potential energy into kinetic energy.

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0

3 years ago

1. The hydrogen balloons which are used to collect weather information from the atmosphere is made of plastic and never complete

Naily [24]

Answer:

Answer:- Volume of the balloon is 5.78 L.

Solution:- There are 0.24 moles of hydrogen gas in a balloon at 35 degree C and 1.05 atm pressure. It asks to calculate the volume of the balloon.

This problem is based on ideal gas law equation:

P = 1.05 atm, n = 0.24 mole, T = 35 + 273 = 308 K

R =

V = ?

The equation could be rearranged for the volume as:

Let's plug in the values and do the calculations to get the volume of the balloon:

V = 5.78 L

So, the volume of the gas balloon is 5.78 L.

5 0

2 years ago

An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and r

torisob [31]

Ans: Intensity = I = $5.8 * 10^{-8} W/m^2$

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = $\sqrt{ \frac{1}{\mu\epsilon} }$

v = $\sqrt{ \frac{1}{\mu_r\mu_ok\epsilon_o} }$
$\mu_r = 5.18 \\
\mu_o = 4 \pi * 10^{-7} \\
k = 3.64 \\
\epsilon_o = 8.85 * 10^{-12}$

Plug in the values:
v = $\sqrt{ \frac{1}{(5.18)(4\pi*10^{-7})(3.64)(8.85*10^{-12})} }$
v = $6.9 * 10^7$ m/s

Now that we have "v", we can use the following formula to find the intensity of wave:

$I = \frac{k\epsilon_o*v*E_{max}^2}{2}$

$I = \frac{(3.64)(8.85*10^{-12})
*(6.9*10^7)*(7.20*10^{-3})^2}{2}$

Intensity = I = $5.8 * 10^{-8} W/m^2$

4 0

3 years ago