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valentina_108 [34]
2 years ago
8

A 1.0 kg ball falls from rest a distance of 19.6 m.

Physics
1 answer:
Nimfa-mama [501]2 years ago
6 0

Answer:

192.08J

19.6m/s

Explanation:

Since there will be no potential energy when the ball is on the ground, the change in potential energy is equal to the potential energy at the start when the ball is 19.6m above the ground.

PE=mgh

=(1)(9.8)(19.6)

=192.08J

v²=u²+2as, where v is the final velocity, u is initial velocity, a is acceleration and s is distance. Initial velocity is 0 since it starts at rest.

v²=u²+2as

v²=0²+2(9.8)(19.6)

v=√384.16

=19.6m/s

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The free body diagram of all the forces on the box is obtained by noting the upward force and downward forces on the box as shown below;

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(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

Learn more about free body diagram of inclined objects here: brainly.com/question/4176810

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