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2 years ago

A 1.0 kg ball falls from rest a distance of 19.6 m.

Physics

1 answer:

Nimfa-mama [501]2 years ago

6 0

Answer:

192.08J

19.6m/s

Explanation:

Since there will be no potential energy when the ball is on the ground, the change in potential energy is equal to the potential energy at the start when the ball is 19.6m above the ground.

PE=mgh

=(1)(9.8)(19.6)

=192.08J

v²=u²+2as, where v is the final velocity, u is initial velocity, a is acceleration and s is distance. Initial velocity is 0 since it starts at rest.

v²=u²+2as

v²=0²+2(9.8)(19.6)

v=√384.16

=19.6m/s

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A 59kg child starting from rest slides down a water slide with a vertical height of 5.0m. what is the child's speed halfway down

KIM [24]

<span>EP (potential energy) = mgy -> (59)(9.8)(-5) = -2,891
EP + EK (kinetic energy) = 0; but rearranging it for EK makes it EK = -EP, such that EK = 2891 when plugged in.
EK = 0.5mv^2, but can also be v = sqrt(2EK/m).
Plugging that in for sqrt((2 * 2891)/59), we get 9.9 m/s^2 with respect to significant figures.</span>

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2 years ago

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Answer:

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The magnetic field intensity is $1.1486813808\times 10^{-7}\ T$

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The electric field intensity is 34.46 V/m

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2 years ago

The wheels of a car have radius 12 in. and are rotating at 600 rpm. Find the speed of the car in mi/h.

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Answer:

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Explanation:

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6 months ago

You are a traffic accident investigator. You have arrived at the scene of an accident. Two cars of equal mass (1,000 kg each) we

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2 years ago

Please help me it's URGENT (#10 btw and also how do I solve for time

Afina-wow [57]

Answer:

t = 12s

Explanation:

Given:

v-initial = 0 m/s

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Solve:

x = (v-initial)t + 1/2(a*t^2)

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2 years ago