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valentina_108 [34]
2 years ago
8

A 1.0 kg ball falls from rest a distance of 19.6 m.

Physics
1 answer:
Nimfa-mama [501]2 years ago
6 0

Answer:

192.08J

19.6m/s

Explanation:

Since there will be no potential energy when the ball is on the ground, the change in potential energy is equal to the potential energy at the start when the ball is 19.6m above the ground.

PE=mgh

=(1)(9.8)(19.6)

=192.08J

v²=u²+2as, where v is the final velocity, u is initial velocity, a is acceleration and s is distance. Initial velocity is 0 since it starts at rest.

v²=u²+2as

v²=0²+2(9.8)(19.6)

v=√384.16

=19.6m/s

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At a fixed depth within a fluid at rest, the pressure pushing upward is
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Explanation:

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6 0
3 years ago
Read 2 more answers
A student witnesses a flash of lightning and then t=2.5s later the student hears assiciated clap of thunder. (please show work)
frosja888 [35]

Answer:

857.5 m

2.8583×10⁻⁶ seconds

Explanation:

Time taken by the sound of the thunder to reach the student = 2.5 s

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Distance travelled by the sound = Time taken by the sound × Speed of sound in air

⇒Distance travelled by the sound = 2.5×343 = 857.5 m

⇒Distance travelled by the sound = 857.5 m

Time taken by light = Distance the light travelled / Speed of light

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3 0
3 years ago
1 point
klio [65]

Answer:

0

10

20

30

40

50

60

70

80

90

100 g

0

100

200

300

400

500

8

9

108

Explanation:

ikkk

8 0
3 years ago
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