Answer:
Approximately (assuming that the car is moving on level ground, and that there is no friction to hinder the motion of the car.)
Explanation:
Formula for the kinetic energy, , of an object of travelling at velocity :
.
Let and denote the velocity of this car before and after the acceleration.
Kinetic energy of this car before the acceleration:
.
Kinetic energy of this car after the acceleration:
.
Assume that this car was travelling on level ground. Also assume that there is no friction to hinder the motion of this car. The work of the engine of this car would be equal to the amount of that the car has gained:
.
True. The amount of water on Earth is consistent even if it is displayed in different forms.
Yes, they live off of other organisms and harm the organisms.
A.
nucleus hold protons and neutrons that contain the mass. but is smaller due to the electron cloud making the atom bigger.
Answer:
a) Vaw = 2.19 mi / h θ = 346.8º b) Vmgx = 0.866 mi / h Vawy = -0.5 mi / h
Explanation:
We using the sum of vectors, we use the indexes ‘a’ for the plane, ‘g’ for the land ‘w’ for the wind,
= +
= +
To facilitate the calculation we decompose with respect to xy coordinate system
= cos 30
= sin30
Vwgx = Vwd cos 30
Vwgx = Vwd sin30
Vmgx = 1.00 cos 30
Vmgx = 0.866 mi / h
Vmgy = 1.00 sin30
Vwgy = 0.5 mi / h
Let's find the resulting components
Vawx = 3.00 -0.866
Vawx = 2,134 mi / h
Vawy = 0 - 0.5
Vawy = -0.5 mi / h
Let's use Pythagoras' theorem
Vaw2 = Vawx2 + Vawy2
Vaw = Ra Vawx2 + Vawy2
Vaw = ra 2,134 2 + 0.52
Vaw = 2.19 mi / h