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VLD [36.1K]
3 years ago
14

An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and r

elative permeability 5.18 at this frequency. the electric field has amplitude 7.20×10−3v/m.what is the intensity of the wave in a medium\?
Physics
1 answer:
torisob [31]3 years ago
4 0
Ans: Intensity = I = 5.8 * 10^{-8} W/m^2

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = \sqrt{ \frac{1}{\mu\epsilon} }


v = \sqrt{ \frac{1}{\mu_r\mu_ok\epsilon_o} }
\mu_r = 5.18 \\
\mu_o = 4 \pi * 10^{-7} \\
k = 3.64 \\
\epsilon_o = 8.85 * 10^{-12}

Plug in the values:
v = \sqrt{ \frac{1}{(5.18)(4\pi*10^{-7})(3.64)(8.85*10^{-12})} }
v = 6.9 * 10^7 m/s

Now that we have "v", we can use the following formula to find the intensity of wave:

I =  \frac{k\epsilon_o*v*E_{max}^2}{2}

I =  \frac{(3.64)(8.85*10^{-12})
*(6.9*10^7)*(7.20*10^{-3})^2}{2}

Intensity = I = 5.8 * 10^{-8} W/m^2

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The addition of vectors involve both magnitude and direction. In this case, we make use of a triangle to visualize the problem. The length of two sides were given while the measure of the angle between the two sides can be derived. We then assign variables for each of the given quantities.

Let:

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We then use the cosine law to find the length of the unknown side. The cosine law results to the formula: a^2 = b^2 + c^2 -2*b*c*cos(A). Substituting the values, we then have: a = sqrt[(8)^2 + (6)^2 -2(8)(6)cos(75°)]. Finally, we have a = 8.6691 m.

Next, we make use of the sine law to get the angle, B, which is opposite to the side B. The sine law results to the formula: sin(A)/a = sin(B)/b and consequently, sin(75)/8.6691 = sin(B)/8. We then get B = 63.0464°. However, the direction of the resultant vector is given by the angle Θ which is Θ = 90° - 63.0464° = 26.9536°.

In summary, the resultant vector has a magnitude of 8.6691 m and it makes an angle equal to 26.9536° with the x-axis.
 
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3 years ago
Belly-flop Bernie dives from atop a tall flagpole into a swimming pool below. His potential energy at the top is 7000 J (relativ
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Answer:

KE₂ = 6000 J

Explanation:

Given that

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