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VLD [36.1K]
3 years ago
14

An electromagnetic wave with frequency 65.0hz travels in an insulating magnetic material that has dielectric constant 3.64 and r

elative permeability 5.18 at this frequency. the electric field has amplitude 7.20×10−3v/m.what is the intensity of the wave in a medium\?
Physics
1 answer:
torisob [31]3 years ago
4 0
Ans: Intensity = I = 5.8 * 10^{-8} W/m^2

Explanation:
First you need to find out the speed of Electromagnetic wave:

Since
v = \sqrt{ \frac{1}{\mu\epsilon} }


v = \sqrt{ \frac{1}{\mu_r\mu_ok\epsilon_o} }
\mu_r = 5.18 \\
\mu_o = 4 \pi * 10^{-7} \\
k = 3.64 \\
\epsilon_o = 8.85 * 10^{-12}

Plug in the values:
v = \sqrt{ \frac{1}{(5.18)(4\pi*10^{-7})(3.64)(8.85*10^{-12})} }
v = 6.9 * 10^7 m/s

Now that we have "v", we can use the following formula to find the intensity of wave:

I =  \frac{k\epsilon_o*v*E_{max}^2}{2}

I =  \frac{(3.64)(8.85*10^{-12})
*(6.9*10^7)*(7.20*10^{-3})^2}{2}

Intensity = I = 5.8 * 10^{-8} W/m^2

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<h3>Explanation</h3>

Refer to the diagram attached (created with GeoGebra). Consider the 5 N force in two directions: parallel to the 8 N force and normal to the 8 N force.

  • \displaystyle F_{\text{1, Parallel}} = F_1 \cdot \cos{45^\textdegree} = \dfrac{5\sqrt{2}}{2}\;\text{N}.
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\displaystyle \Sigma F = \sqrt{{(8 + \dfrac{5\sqrt{2}}{2})}^2 + {(\dfrac{5\sqrt{2}}{2})}^2} = 12.1\;\text{N} (3 sig. fig.).

The size of the angle between the resultant force and the 8 N force can be found from the tangent value of the angle. Tangent of the angle:

\displaystyle \dfrac{\Sigma F_\text{Normal}}{\Sigma F_\text{Parallel}} = \dfrac{8 + \dfrac{5\sqrt{2}}{2}}{\dfrac{5\sqrt{2}}{2}} \approx 0.306491.

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\displaystyle \arctan{ \dfrac{\Sigma F_\text{Normal}}{\Sigma F_\text{Parallel}}} = \arctan{0.306491} = 17.0\textdegree.

In other words, the resultant force is 17.0° relative to the 8 N force.

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