The main formula of derivative
if g(x) = a^x, so g'(x) = a^x. lna, a>0, a # 1,
so g ' (x) = [(2ra^(rx)+n)^p] = 2r.a^(rx)+n)^p . ln a
so g ' (x) = 2r. ln a. a^(rx)+n)^p
Answer:
17
Step-by-step explanation:
Substitute the value of the variable and simplify.



Anything raised to the power of 0 is one.
16 + 1 = 17
Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?
Answer:
-16
Step-by-step explanation:
So let’s solve for 7x. So 7x=34. So 7x-50 is 34-50 or -16