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mel-nik [20]
3 years ago
10

An elevator is rising up a vertical shaft in a skyscraper. Between the 12th and 20th floors, it travels at a constant speed. Dur

ing this time period:
1.) The only unbalanced force acting on it is air resistance.

2.) The forces acting on it are balanced so the net force is zero.

3.) The upward force is greater than the combined downward forces of gravity and air resistance, making it move upward.

4.) There are no forces acting on it so the net force is zero.
Physics
1 answer:
zaharov [31]3 years ago
8 0
3. The upward force is greater
.................,
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Answer:

g(h) = g ( 1 - 2(h/R) )

<em>*At first order on h/R*</em>

Explanation:

Hi!

We can derive this expression for distances h small compared to the earth's radius R.

In order to do this, we must expand the newton's law of universal gravitation around r=R

Remember that this law is:

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and

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a(R+h) \approx G\frac{m_1}{R^2} -2G\frac{m_1}{R^2} \frac{h}{R} = g(1-2\frac{h}{R})

Consider that the error in this expresion is quadratic in (h/R), and to consider quadratic correctiosn you must expand the taylor series to the next power:

a(R+h) \approx a(R) + h \frac{da(r)}{dr}_{r=R} + \frac{h^2}{2!} \frac{d^2a(r)}{dr^2}_{r=R}

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