Answer:
1) 3.1 m/s
2) 7 m/s
Explanation:
Distance due north = 80 m
Distance due south = 30 m
Distance between north and south = (80 - 30) m = 50 m
Total time = (12 + 4) sec = 16 sec
1) Average speed = 50/16 = 3.1 m/s
2) Average velocity = Total distance/total time = (80 + 30) m/16 s = 110/16 = 7 m/s
Answer:
Average net force, F = 15157.15 N
Explanation:
It is given that,
The mass of the car and riders is, 
Initial speed of the car, u = 0
Final speed of the car, v = 43.4 m/s
Time, t = 8.59 seconds
We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :
F = m a


F = 15157.15 N
So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.
Answer:
217.43298 m/s
Explanation:
= Mass of bullet = 19 g
= Mass of bob = 1.3 kg
L = Length of pendulum = 2.3 m
= Angle of deflection = 60°
u = Velocity of bullet
Combined velocity of bullet and bob is given by

As the momentum is conserved

The speed of the bullet is 217.43298 m/s
Answer:
31.75 m/s
Explanation:
h = 41.7 m
Let the initial velocity of the second stone is u
Let the time taken to reach to the bottom by the first stone is t then the time taken by the second stone to reach the ground is t - 1.8.
For first stone:
Use second equation of motion

Here, u = 0, g = 9.8 m/s^2 and t be the time and h = 41.7
So, 41.7= 0 + 0.5 x 9.8 x t^2
41.7 = 4.9 t^2
t = 2.92 s ..... (1)
For second stone:
Use second equation of motion

Here, g = 9.8 m/s^2 and time taken is t - 1.8 = 2.92 - 1.8 = 1.12 s, h = 41.7 m and u be the initial velocity
.... (2)
By equation the equation (1) and (2), we get

u = 31.75 m/s