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Andrej [43]
4 years ago
13

What is a newton equal to in terms of mass and acceleration

Physics
1 answer:
Andre45 [30]4 years ago
8 0
1 newton is the force that accelerates 1 kilogram of mass at the rate of 1 meter per second^2. / / / 1N = 1 kg-m / sec^2 .
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This diagram of the first right-hand rule relates which two quantities?
AURORKA [14]

Option A, current (thumb) to magnetic field (fingers)

As per the First right-hand rule,

Using right hand, if we suppose that thumb points towards the electric current

fingers curl towards the magnetic field

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3 years ago
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Why do people bleed .-.
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3 0
3 years ago
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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.75 m/s. If the roof is pitched at
dalvyx [7]

Answer:

a) t = 0.528 s

b) D = 1.62 m

Explanation:

given,

speed of the baseball = 3.75 m/s

angle made with the horizontal = 35°

height of the roof edge = 2.5 m

using equation of motion

s = ut +\dfrac{1}{2}gt^2

2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2

2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2

4.9 t² + 2.15 t - 2.5 = 0

on solving the above equation

t = 0.528 s

b) D = v cos θ × t

D = 3.75 × cos 35° ×0.528

D = 1.62 m

3 0
4 years ago
Slope or velocit ime graph represent
Lubov Fominskaja [6]

Answer:

Please check the explanation.

Explanation:

The slope of the velocity-time graph illustrates the change in velocity with respect to change in time.

In other words, the acceleration of the object is defined by the slope of a velocity graph. The acceleration can be obtained by finding the slope at a particular time.

Hence, the slope of the velocity time graph represent represents acceleration.

2. Also the acceleration of any object, like a car or bike, at some discrete instant in time 't' is termed as instantaneous acceleration which can be determined if we may take the derivate of the given velocity function.

3. A vector that has a direction and magnitude of 1 is termed as a unit vector, often called a direction vector.

7 0
3 years ago
There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. Part A A p
tamaranim1 [39]

Explanation:

A pilot flying a weight; it takes t = 3.4 s to hit the ground, during which it travels a horizontal distance d = 120 m  

h = g/2*t^2

h= 4.903*3.4^2

h=56.701 m

V = d/t

V= 120/3.4

V=35.3 m/sec  

Now the pilot does a run at the same height but twice the speed.  

How much time (t1) does it take the weight to hit the ground?

t1 = t = 3.4 sec (depending just upon height)

5 0
3 years ago
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