Answer:
Part a)
Part b)
Part C)
Part d)
Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.
Explanation:
Part a)
As we know that car A moves by distance 6.1 m after collision under the frictional force
so the deceleration due to friction is given as
now we will have
Part b)
Similarly for car B the distance of stop is given as 4.4 m
so we will have
Part C)
By momentum conservation we will have
Part d)
Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.
The approximate volume of table tennis ball is 80 cm³
<h3>What is volume?</h3>
Volume is defined as the amount of space occupied by the three dimensional object. S I unit of volume is m³ or cm³.
To find the volume of tennis ball using graduated cylinder.
Step 1 - Fill the graduated cylinder half or full.
Step 2 - Mark the initial volume of the water i.e. 100 cm³ (Vi)
Step 3 - Put the tennis ball in the graduated cylinder. Some of the water was displaced by the table tennis ball.
Step 4 - Mark the Final volume of the water (Vf) i.e. 180 cm³
Step 5 = Calculate the volume by using Formula
Vb = Vf – Vi = 180 cm³ - 100 cm³ = 80 cm³
Hence the volume of tennis ball (Vb) is 80 cm³
For more Volume related question visit here:
brainly.com/question/14996332
#SPJ1
<h2>
Answer:</h2>
D. (1m, 0.5m)
<h2>
Explanation:</h2>
The center of mass (or center of gravity) of a system of particles is the point where the weight acts when the individual particles are replaced by a single particle of equivalent mass. For the three masses, the coordinates of the center of mass C(x, y) is given by;
x = (m₁x₁ + m₂x₂ + m₃x₃) / M ----------------(i)
y = (m₁y₁ + m₂y₂ + m₃y₃) / M ----------------(ii)
Where;
M = sum of the masses
m₁ and x₁ = mass and position of first mass in the x direction.
m₂ and x₂ = mass and position of second mass in the x direction.
m₃ and x₃ = mass and position of third mass in the x direction.
y₁ , y₂ and y₃ = positions of the first, second and third masses respectively in the y direction.
From the question;
m₁ = 6kg
m₂ = 4kg
m₃ = 2kg
x₁ = 0m
x₂ = 3m
x₃ = 0m
y₁ = 0m
y₂ = 0m
y₃ = 3m
M = m₁ + m₂ + m₃ = 6 + 4 + 2 = 12kg
Substitute these values into equations (i) and (ii) as follows;
x = ((6x0) + (4x3) + (2x0)) / 12
x = 12 / 12
x = 1 m
y = (6x0) + (4x0) + (2x3)) / 12
y = 6 / 12
y = 0.5m
Therefore, the center of mass of the system is at (1m, 0.5m)
Answer:
Hello friend where is the figure of the question
