Avg sped = total distance/ total time = 1350 mi/ 5 hrs= 270mph (i dont know if ur teacher wants you to convert this to m/s)
300miles are traveled in 1 hr. So, 300 *2hrs = 600 miles south
750/250= 3hrs north
Total distance = 600 miles + 750 miles= 1350 miles
Total time is = 3hrs + 2hrs= 5hrs
<span>The photoelectric effect is about electrons being ejected from metals when light is shined on metals. The electrons do not behave like waves in the photoelectric effect. Black body radiation is all about the radiation emitted by warm bodies and not about those bodies behaving like waves. The emission spectra of atoms is all about what light is given off by atoms when electrons in those atoms jump down to lower energy levels from higher levels. That also has nothing to do with matter behaving as a wave. Interference is classically defined as the generation of a new wave with an amplitude modulated according to the waves that interfere to form that new wave. Note its emphasis on the wave part.</span>
Answer:
A) a = 73.304 rad/s²
B) Δθ = 3665.2 rad
Explanation:
A) From Newton's first equation of motion, we can say that;
a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.
Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s
Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s
We are given; t = 10 s
Thus;
a = 733.04/10
a = 73.304 rad/s²
B) From Newton's third equation of motion, we can say that;
ω² = ω_o² + 2aΔθ
Where Δθ is angular displacement
Making Δθ the subject;
Δθ = (ω² - ω_o²)/2a
At this point, ω = 0 rad/s while ω_o = 733.04 rad/s
Thus;
Δθ = (0² - 733.04²)/(2 × 73.304)
Δθ = -537347.6416/146.608
Δθ = - 3665.2 rad
We will take the absolute value.
Thus, Δθ = 3665.2 rad
You have to use the specific heat equation.
Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.
So we can substitute our variables into the equation.
30000J = (390g)(3.9J*g/C)ΔT
Solving for ΔT, we get:
30000J/[(390g)*(3.9J*g/C) = ΔT
ΔT = 19.72386588C
I'm assuming the temperature is C, since it was not specified.
Hope this helps!
Answer:
b.
Explanation:
In case of Single Slit, diffraction will occur.
Then In Single slit Diffraction, width of central fringe is
where D= distance b/w screen and slit
a= slit width
\lambda = wavelength
Thus if Screen width increases keeping other factors same then width of central fringe becomes narrower as
On increasing the slit width the central bright fringe width The width of the central bright fringe becomes narrower.
