The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.
Ideal gas behavior:
Suppose the initial volume of carbon dioxide gas is V = 3.5l
Initial pressure is P = 125 kPa
Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L
The final pressure of the gas is P'.
We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.
PV = P'V'
125 × 3.5 = P'× 2
P'= 218.75 kPa
Therefore, the final pressure is 218.5 kPa.
Learn more about ideal gas, visit brainly.com/question/11676583?referrer=searchResults
#SPJ4
Answer:
The 2 numbers are 14 and 17.
Step-by-step explanation:
Let the 2 numbers be x and y.
x + 11 = 2y
x - 2y = -11...............A
y +20 = 2x
2x - y = 20 ...............B
Multiply equation A by -2:
-2x + 4y = 22............C
Adding B and C :-
3y = 42
y = 14.
Substitute y = 14 in equation A:
x - 2(14) = -11
x = -11 + 28
x = 17.
The answer is b. The others don’t make sense
Answer:
$70.51
Step-by-step explanation:
58.76 x 1.20 = $70.51 this is multiplying by 120%
you could also multiply by .2 x 58.76 = 11.75 which is the amount of the tip and add it to 58.76. giving you the same answer.
Answer:
(4.5,7)
Step-by-step explanation:
Medpoint= x one + x two ÷2 , y one + y two ÷2