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prohojiy [21]
3 years ago
9

Can someone help me?

Mathematics
1 answer:
shusha [124]3 years ago
6 0

B. \sqrt{x}  +  \sqrt{x - 1} ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\frac{1}{ \sqrt{x} -  \sqrt{x - 1}  }  \\  \\=  \frac{1}{ \sqrt{x} -  \sqrt{x - 1}  }  \times  \frac{ \sqrt{x}  +  \sqrt{x - 1} }{ \sqrt{x} +  \sqrt{x - 1}  }  \\ \\  =  \frac{ \sqrt{x}  +  \sqrt{x - 1} }{  ({ \sqrt{x} })^{2}   -  { (\sqrt{x - 1} })^{2} }  \\\\ [∵(a + b)(a - b) =  {a}^{2}  -  {b}^{2} ] \\  \\=  \frac{ \sqrt{x} +  \sqrt{x - 1}  }{x - (x - 1)}  \\  \\=  \frac{ \sqrt{x}  +  \sqrt{x - 1} }{ x - x +  1}  \\  \\=   \sqrt{x}   +  \sqrt{x - 1}

\bold{ \green{ \star{ \orange{Mystique35}}}}⋆

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Data collected over a long period of time show that the length of time x to complete a particular college entrance test is norma
Finger [1]

Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.

For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.

First, solve for the z-score using the formula below.

z-score = (x – μ) / σ

where x = individual data value = 100

μ = mean = 125

σ = standard deviation = 18

z-score = (100 – 125) / 18

z-score = (-25) / 18

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Find the probability that corresponds to the z-score in the z-table. (see attached images)

-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968

-0.09 : -0.1 = x - 0.0968 : -0.016

x - 0.0968 = -0.09(-0.016)/-0.1

x = -0.0144 + 0.0968

x = 0.0824

x = 0.0824

Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.

Learn more about probability here: brainly.com/question/26822684

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