What is the solution for -3x ≥ 36?
2 answers:
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Answer:
Step-by-step explanation:
We have to take the derivatives for both functions and replace in the differential equation. Hence
for y=e^{-5x}:
for y=e^{6x}:
Now we replace in the differential equation y'' − y' − 30y = 0
for y=e^{-5x}:
for y=e^{6x}:
Now, to know if both function are linearly independent we calculate the Wronskian
I hope this is useful for you
Best regard
Answer:
13.16 miles
Step-by-step explanation:
The attached diagram is a scale representation of the geometry, but shown upside down from the figure given in the problem statement. The tangent ratio is useful for solving this problem, as it relates the legs of the triangle to the angle of interest.
The basic relation is ...
Tan = Opposite/Adjacent
Applying this to the given angles, we have ...
tan(36°) = EG/AG . . . . . [eq1]
tan(43°) = EG/DG = EG/(AG -4) . . . . . [eq2]
Multiplying both equations by their denominators, we can eliminate the fractions:
AG·tan(36°) = EG . . . . . [eq3]
(AG -4)·tan(43°) = EG . . . . . [eq4]
Equating expressions for EG, we have ...
AG·tan(36°) = (AG -4)·tan(43°)
4·tan(43°) = AG(tan(43°) -tan(36°))
AG = 4·tan(43°)/(tan(43°) -tan(36°)) . . . . . [eq5]
Substituting into [eq3], we find ...
EG = 4·tan(36°)·tan(43°)/(tan(43°) -tan(36°))
EG ≈ 4(0.72644)(0.93252)/(0.93252 -0.72654) ≈ 13.1573 . . . . miles
The plane is flying at an altitude of about 13.16 miles.
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<em>Additional comment</em>
That's about 69,500 feet. The operational ceiling of most passenger aircraft is below 51,000 feet. The U2 reconnaissance aircraft reportedly has a service ceiling of about 70,000 feet.
