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Law Incorporation [45]
3 years ago
14

Derive the equation of the parabola with a focus at (−2, 4) and a directrix of y = 6. Put the equation in standard form.

Mathematics
2 answers:
disa [49]3 years ago
8 0

Answer:

Option B

Step-by-step explanation:

Given that a parabola has a focus at (−2, 4) and a directrix of y = 6.

We have to find the equation of the parabola in std form

We know that a parabola is a conic section in which all points are equidistant from the focus and vertex.

Let (x,y) be any point on the parabola

Distance of (x,y) from the focus =\sqrt{(x+2)^2+(y-4)^2} ...i

Distance of (x,y) from directrix = difference in y coordinate = |y[-6|...ii

Since i = ii, square and equate both

(x+2)^2+(y-4)^2=(y-6)^2\\x^2+4x+4 -8y+16 = -12y+36\\4y=-x^2-4x+16\\y = \frac{-1}{4} d^2-x+4

Hence option B is right.

erastovalidia [21]3 years ago
3 0

Answer:

B

Step-by-step explanation:

From any point (x, y) on the parabola the focus and directrix are equidistant.

Using the distance formula

\sqrt{(x+2)^2+(y-4)^2} = | y - 6 |

Squaring both sides

(x + 2)² + (y - 4)² = (y - 6)² ←  distributing

x² + 4x + 4 + y² - 8y + 16 = y² - 12y + 36 ( subtract y² - 12y + 36 from both sides )

x² + 4x + 4 + 4y - 20 = 0 ( subtract x² + 4x + 4 from both sides )

4y - 20 = - x² - 4x - 4 ( add 20 to both sides )

4y = - x² - 4x + 16 ( divide through by 4 )

y = - \frac{1}{4} x² - x + 4, that is

f(x) = - \frac{1}{4} x² - x + 4 → B

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