Only answer if you know it!
2 answers:
You might be interested in
The question is incomplete. Here is the complete question.
An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.
Answer: v% = 0.21 m/s
Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that: ΔpΔx≥
where h is <u>Planck's constant</u> and it is equal to 6.626.m²kg/s.
Since p (momentum) is p = m.v:
mΔv.Δx ≥
Δv =
Given that: r = x = 1.54.m and mass of an electron is m=9.1.
kg
Δv =
Δv = 0.0376.
As percentage of average speed:
Δv..100% =
.10² = 0.021.10 = 0.21%
The least possible uncertainty in a speed of an electron is 0.21%.