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3 years ago

Arrange the events in the life of a star in the correct order.

Chemistry

1 answer:

tatiyna3 years ago

3 0

Answer:

1. The temperature increases in the center of a nebula, and nuclei begin to fuse.

2. As the nuclear fusion sets off a chain reaction, the nebula gets hotter and brighter and turns into a star.

3. The star stays in the main sequence stage for a long time.

4. The star runs out of hydrogen and turns into a planetary nebula or a supernova, depending on its mass.

5. Heavy elements are created when the supernova explodes.

6. All that remains of the star now is the core. In some cases, the star turns into a black hole.

Explanation:

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The scientific method is one application of critical thinking.true or false

kumpel [21]

The best answer between the two choices would be the first option TRUE because the scientific method is used to do more advance research and investigation on things.

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3 years ago

Read 2 more answers

Balanced equation for Co+O2=Co2O3

Reptile [31]

Answer:

4 Co(s) + 3 O2(g) = 2 Co2O3(s)

Explanation:

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2 years ago

You pre-weigh a glass vial to hold your sample and find its mass to be 5.010 g. You add your sample to the vial and reweigh it o

san4es73 [151]

Answer : 1.12 grams

Yo find the mass of the sample, you take the increased mass and subtract the original mass.

6.130 - 5.010 = 1.12

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2 years ago

It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta

Zigmanuir [339]

Answer:

$\lambda=241.9\ nm$

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,

1 mole = $6.023\times 10^{23}\ electrons$

So,

$6.023\times 10^{23}$ electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of $\frac {495.0}{6.023\times 10^{23}}\ kJ$ of energy.

Energy required = $82.18\times 10^{-23}\ kJ$

Also,

1 kJ = 1000 J

So,

Energy required = $82.18\times 10^{-20}\ J$

Also, $E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

So,

$79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}$

$\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}$

$\lambda=\frac{19.878}{10^6\times \:82.18}$

$\lambda=2.4188\times 10^{-7}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=241.9\ nm$

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3 years ago

Write the chemical formula, condensed formula, and Lewis structure for each of the following hydrocarbons:

son4ous [18]

Explanation:

Here I send you all the 3 elements that you are asking for.

Notice that first on the left you will find lewis structure, then condensed and finally chemical formula of each of the compound you enlisted.

5 0

2 years ago