Answer:
The molarity (M) of the following solutions are :
A. M = 0.88 M
B. M = 0.76 M
Explanation:
A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.
Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)
= 27 + 3(16 + 1)
= 27 + 3(17) = 27 + 51
= 78 g/mole
= 78 g/mole
Given mass= 19.2 g/mole


Moles = 0.246

Volume = 280 mL = 0.280 L

Molarity = 0.879 M
Molarity = 0.88 M
B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr
Molar mass of KBr = 119 g/mole
Given mass = 235.9 g

Moles = 1.98
Volume = 2.6 L


Molarity = 0.762 M
Molarity = 0.76 M
Answer:
P = 1/8
Explanation:
The wave function of a particle in a one-dimensional box is given by:

Hence, the probability of finding the particle in the one-dimensional box is:


Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:
Solving for n=4:
I hope it helps you!
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>
Solving:
1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule
6,02*10²³X = 75

The required net ionic equation is; 2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)
The molecular reaction equation is;
H2SeO3(aq) + 2KOH(aq) -----> K2SeO3(aq) + 2H2O(l)
The complete ionic equation is;
2H^+(aq) + SeO3^2-(aq) + 2K^+(aq) + 2OH^-(aq)-----> 2K^+(aq) + SeO3^2-(aq) + 2H2O(l)
Net ionic equation;
2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)
We can clearly see that this is a neutralization reaction hence water is the product of the net ionic equation.
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